通常运行无限bash循环,我执行以下操作:
while true; do
echo test
sleep 1
done
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如果相反,我想做一个无限循环的循环,只要它早于20:00.有没有办法在bash中这样做?
You can use date
to print the hours and then compare to the one you are looking for:
while [ $(date "+%H") -lt 20 ]; do
echo "test"
sleep 1
done
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as date "+%H"
shows the current hour, it keeps checking if we are already there or in a "smaller" hour.
如果您想要特定的日期,而不仅仅是完整的时间,请尝试比较 Unix 时间:
while [ $(date +%s) -lt $(date --date="2016-11-04T20:00:00" +%s) ]; do
echo test
sleep 1
done
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