在捷克语中对数组进行排序,localeCompare

Question

我有问题用捷克名称排序数组.它适用于普通字符,但不适用于特殊字符.'Sb','St','Šk'; 特殊的Š应该在其他两个词之后,但它以不同的顺序结束.这是一个简单的代码.

var tmpArr = ['Sb', 'BE', 'De', 'CS', 'Au', 'Šk', 'De', 'St', 'Ci', 'št'];

function mySort(s1, s2) {
return s1.localeCompare(s2 ,'cz', {sensitivity: "variant"});
}

var sorted = tmpArr.sort(mySort);

console.log(tmpArr);

for(var i in sorted){
console.log(sorted[i]);
}

这应该也适用于所有浏览器.

Answer 1

DobrýDen,

因为这说明

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/localeCompare

在常见浏览器中未实现区域设置比较的高级选项.

如果你只需要Chech语言,那么最好使用字符映射来实现你自己的字符串比较:

var charMapL = " 0123456789aábc?d?eé?fghiíjklmn?oópqr?sšt?uú?vwxyýzž";
var charMapU = " 0123456789AÁBC?D?EÉ?FGHIÍJKLMN?OÓPQR?SŠT?UÚ?VWXYÝZŽ";
var charsOrder = {};
for(var i in charMapL.split('')) {
    charsOrder[charMapL[i]] = parseInt(i);
    charsOrder[charMapU[i]] = parseInt(i);
}

function mySort(s1, s2) {
    var idx = 0;
    while ( (idx < s1.length) && (idx < s2.length) && (charsOrder[s1[idx]] == charsOrder[s2[idx]])) {
        idx ++;
    }
    if ((idx == s1.length) && (idx == s2.length)) return 0;
    if (idx == s1.length) return 1;
    if (idx == s2.length) return -1;
    return charsOrder[s1[idx]] > charsOrder[s2[idx]] ? 1 : (charsOrder[s1[idx]] < charsOrder[s2[idx]] ? -1 : 0);
}

console.log(tmpArr);
tmpArr.sort();
console.log(tmpArr);
tmpArr.sort(mySort);
console.log(tmpArr);

http://jsfiddle.net/GNNBc/1/