python中的check_output错误

Question

我在运行以下代码时遇到错误.

#!/usr/bin/python
import subprocess
import os
def check_output(*popenargs, **kwargs):
    process = subprocess.Popen(stdout=subprocess.PIPE, *popenargs, **kwargs)
    output, unused_err = process.communicate()
    retcode = process.poll()
    if retcode:
        cmd = kwargs.get("args")
        if cmd is None:
            cmd = popenargs[0]
        error = subprocess.CalledProcessError(retcode, cmd)
        error.output = output
        raise error
    return output

location = "%s/folder"%(os.environ["Home"])
subprocess.check_output(['./MyFile'])

错误

subprocess.check_output(['./MyFile'])
AttributeError: 'module' object has no attribute 'check_output'

我正在努力Python 2.6.4.

Answer 1

您可能只是想使用check_output,但是,您知道,有一个方法subprocess.check_output,但直到Python 2.7(http://docs.python.org/3/library/subprocess.html#subprocess.check_output)才定义它.

您甚至可能想要这个,它定义了模块中的功能(如果它不存在)(即在v2.7之前运行).

try: subprocess.check_output
except: subprocess.check_output = check_output
subprocess.check_output()

Answer 2

只需使用:

check_output(['./MyFile'])

您已经定义了自己的函数,它不是subprocess模块的属性(对于Python 2.6及更早版本).

您还可以将该函数分配给导入的模块对象(但这不是必需的):

subprocess.check_output = check_output
location = "%s/folder" % (os.environ["Home"])
subprocess.check_output(['./MyFile'])