在sql server中将"&lt;"和"&gt;"替换为"<"和">"

Kun*_*esh 11 sql-server for-xml for-xml-path

嗨,我是xml的新手

我有这样的查询

SELECT  ProjectId, 
       ProjectCode, 
       ProjectName, 
       TechId, 
      -- LocationId, 

      ( SELECT GeoId,PoliticalDivisionId ,GeographicLocationName,IsoCode,Longitude,Latitude,ParentLocationId,
       t2.CreatedBy,t2.CreatedOn,t2.LastUpdatedBy,t2.LastUpdatedOn
    FROM GeographicLocation t2
    WHERE GeoId = t1.LocationId
    FOR XML  PATH('Location') ),
       RtoId, 
       CreatedBy,
       CreatedOn,
       LastUpdatedBy,
       LastUpdatedOn
FROM Project t1
where ProjectId=1
FOR XML PATH('ProjectInfo')
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它将xml返回为

<ProjectInfo>
<ProjectId>1</ProjectId>
<ProjectCode>US-W1-00001</ProjectCode>
<ProjectName>Rees</ProjectName>
<TechId>1</TechId>
&lt;Location&gt;&lt;GeoId&gt;235&lt;/GeoId&gt;&lt;PoliticalDivisionId&gt;2&lt;/PoliticalDivisionId&gt;&lt;GeographicLocationName&gt;UNITED STATES&lt;/GeographicLocationName&gt;&lt;IsoCode&gt;US&lt;/IsoCode&gt;&lt;/Location&gt;
<RtoId>3</RtoId>
<CreatedBy>1</CreatedBy>
<CreatedOn>2013-06-30T20:55:21.587</CreatedOn>
<LastUpdatedBy>1</LastUpdatedBy>
<LastUpdatedOn>2013-06-30T20:55:21.587</LastUpdatedOn>
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prject标签以<和>的形式显示.但是Location的内部标签显示为"<"和">"如何用<和>替换它们

更新:问题中出现了一个小错误.内部xml不适用于rtoid,它适用于位置

我将查询更新为

SELECT  ProjectId, 
       ProjectCode, 
       ProjectName, 
       TechId, 
      -- LocationId, 

      replace(replace( ( SELECT GeoId,PoliticalDivisionId ,GeographicLocationName,IsoCode,Longitude,Latitude,ParentLocationId,
       t2.CreatedBy,t2.CreatedOn,t2.LastUpdatedBy,t2.LastUpdatedOn
    FROM GeographicLocation t2
    WHERE GeoId = t1.LocationId
    FOR XML  PATH('Location') ), '&lt;', '<'), '&gt;', '>'),
       RtoId, 
       CreatedBy,
       CreatedOn,
       LastUpdatedBy,
       LastUpdatedOn
FROM Project t1
where ProjectId=1
FOR XML PATH('ProjectInfo')
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但仍然是一样的

小智 13

我认为正确的方法是使用TYPE指令

SELECT  ProjectId, 
        ...,
      ( SELECT Geo, ...
        FROM GeographicLocation t2
        WHERE GeoId = t1.LocationId
        FOR XML  PATH('Location'), TYPE),
       RtoId,                      ^^^^
       ...
FROM Project t1
where ProjectId=1
FOR XML PATH('ProjectInfo') 
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  • 这是正确的答案——我把所有的旧代码都留在了上一家公司,这个答案让我不再烦恼。非常感谢! (2认同)

Gor*_*off 10

我发现的方式是明确替换它们:

select ProjectId, ProjectCode, ProjectName, TechId,
       replace(replace(RtoId, '&lt;', '<'), '&gt;', '>') as RtoId, 
       . . .
from (<your query here>)
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