使用 DOMResult 进行 XML 转换

4 java xml xslt

java.lang.NullPointerException当我取消注释以下代码中的一行时,我得到了:

private static Document XSLT(String name) throws Exception{
    File xsl = new File("data/" + name + ".xsl");
    File xml = new File("data/" + name + ".xml");
    DocumentBuilder db = DocumentBuilderFactory.newInstance().newDocumentBuilder();
    Document document = db.newDocument();
    DOMSource input = new DOMSource(db.parse(xml));
    StreamResult output = new StreamResult(System.out); //That works but its not what I want!
    //DOMResult output = new DOMResult(document); //that gives the null pointer exception
    TransformerFactory.newInstance().newTransformer(new StreamSource(xsl)).transform(input, output);
    return document;
}
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我的目的是创建一个这样的方法来帮助我转换 XML 文件,同时使用 XSLT 和 Java 语言。毕竟我应该在将其保存到文件之前进行所有转换。

如何从该方法中获取文档?

我的意思是,我想在不将转换后的文档保存到文件中以便能够加载它的情况下执行此操作,我只想在“内存”中执行此操作。

谢谢 :)

更新

让我发布异常,以便您可以更好地帮助我。

Exception in thread "main" javax.xml.transform.TransformerException: java.lang.NullPointerException
        at com.sun.org.apache.xalan.internal.xsltc.trax.TransformerImpl.transform(TransformerImpl.java:736)
        at com.sun.org.apache.xalan.internal.xsltc.trax.TransformerImpl.transform(TransformerImpl.java:340)
        at test.Main.XSLT(Main.java:393)
        at test.Main.test(Main.java:342)
        at test.Main.main(Main.java:329)
Caused by: java.lang.NullPointerException
        at com.sun.org.apache.xml.internal.serializer.SerializerBase.patchName(SerializerBase.java:271)
        at com.sun.org.apache.xml.internal.serializer.SerializerBase.addAttribute(SerializerBase.java:429)
        at com.sun.org.apache.xml.internal.serializer.ToSAXHandler.addUniqueAttribute(ToSAXHandler.java:438)
        at xmlname.template$dot$0()
        at xmlname.applyTemplates()
        at xmlname.transform()
        at com.sun.org.apache.xalan.internal.xsltc.runtime.AbstractTranslet.transform(AbstractTranslet.java:611)
        at com.sun.org.apache.xalan.internal.xsltc.trax.TransformerImpl.transform(TransformerImpl.java:729)
        ... 4 more
---------
java.lang.NullPointerException
        at com.sun.org.apache.xml.internal.serializer.SerializerBase.patchName(SerializerBase.java:271)
        at com.sun.org.apache.xml.internal.serializer.SerializerBase.addAttribute(SerializerBase.java:429)
        at com.sun.org.apache.xml.internal.serializer.ToSAXHandler.addUniqueAttribute(ToSAXHandler.java:438)
        at xmlname.template$dot$0()
        at xmlname.applyTemplates()
        at xmlname.transform()
        at com.sun.org.apache.xalan.internal.xsltc.runtime.AbstractTranslet.transform(AbstractTranslet.java:611)
        at com.sun.org.apache.xalan.internal.xsltc.trax.TransformerImpl.transform(TransformerImpl.java:729)
        at com.sun.org.apache.xalan.internal.xsltc.trax.TransformerImpl.transform(TransformerImpl.java:340)
        at test.Main.XSLT(Main.java:393)
        at test.Main.test(Main.java:342)
        at test.Main.main(Main.java:329)
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更新 2

让我们用一个共同的来源进行测试。

测试文件

<?xml version="1.0" encoding="UTF-8"?>
<tests>
    <test>
        <text>Hi!</text>
    </test>
</tests>
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测试.xsl

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

    <xsl:output 
        method="html"
        version="1.0" 
        encoding="utf-8" 
        indent="yes" 
        omit-xml-declaration="no"
        media-type="application/xml"
        doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN" 
        doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"
    />

    <xsl:template match="/">
        <html xmlns="http://www.w3.org/1999/xhtml" lang="pt-BR" xml:lang="pt-BR">           
            <head>
                <meta charset="UTF-8" />
                <title>Test</title>
            </head>
            <body>
                <h1>Test</h1>                       
                <xsl:apply-templates/>
            </body>
        </html> 
    </xsl:template>

    <xsl:template match="/tests/test">
       <p><xsl:value-of select="text"/></p>
    </xsl:template>

</xsl:stylesheet>
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使用 给出以下输出StreamResult

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html lang="pt-BR" xml:lang="pt-BR" xmlns="http://www.w3.org/1999/xhtml">
<head>
<META http-equiv="Content-Type" content="text/html; charset=utf-8">
<meta charset="UTF-8">
<title>Test</title>
</head>
<body>
<h1>Test</h1>

<p>Hi!</p>

</body>
</html>
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解决了

在适当的地方查看我的答案(在答案中!)

Rav*_*yal 5

DOMResult output = new DOMResult();
TransformerFactory.newInstance().
                   newTransformer(new StreamSource(xsl)).
                   transform(input, output);
return (Document) output.getNode();
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参考:
DOMResult#getNode()

获取将包含结果 DOM 树的节点。如果没有通过 DOMResult(Node node), ... 设置节点,则该节点将由转换设置,并且一旦转换完成就可以从该方法中获取。