我有三个Ruby数组:
[1, 2, 3, 4]
[2, 3, 4, 5]
[3, 4, 5, 6]
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如何获取位置0,位置1等所有三个数字的平均值,并将它们存储在一个名为"平均"的新数组中?
a = [1, 2, 3, 4]
b = [2, 3, 4, 5]
c = [3, 4, 5, 6]
a.zip(b,c)
# [[1, 2, 3], [2, 3, 4], [3, 4, 5], [4, 5, 6]]
.map {|array| array.reduce(:+) / array.size }
# => [ 2,3,4,5]
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