PHP对象不会回显属性

Question

我正在尝试在codeacademy上学习PHP OOP,我想我会疯了.我已经将我的代码与示例代码进行了比较,并且它不会起作用!当我尝试从类Person中创建的对象$ student中回显age属性时,请帮助我理解这里出了什么问题

  <?php
    class Person {
        public $isAlive = true;
        public $firstname;
        public $lastname;
        public $age;
        public function __contruct($firstname, $lastname, $age) 
        {
           $this->firstname = $firstname;
           $this->lastname = $lastname;
           $this->age = $age;
       }
   }
   $teacher = new Person("boring", "12345", 12345);
   $student = new Person('hans', 'hansen', 24);
   $me = new Person('boring', '12345', 12345);
   echo $student->age;
  ?>

Answer 1

你拼错了'构造',所以没有设置.