Julia请求脚本中的用户输入

eja*_*ang 27 julia

如何从Julia中运行的脚本请求用户输入?在MATLAB中,我会这样做:

result = input(prompt)
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谢谢

Joh*_*ite 26

最简单的事情是readline(stdin).这就是你要找的东西吗?

  • 我们可以为此拥有一个更复杂的readline-library-like系统,但是现在这可以解决问题.Keno的纯Julia重新实现我们的repl将为这样的交互式东西提供一个很好的框架. (5认同)
  • 在julia 0.7及之后(可能是0.6),现在是`stdin`. (2认同)

Sal*_*apa 17

正如@StefanKarpinski所指出的那样,它将在未来得到解决,这就是我现在所做的:

julia> @doc """
           input(prompt::String="")::String

       Read a string from STDIN. The trailing newline is stripped.

       The prompt string, if given, is printed to standard output without a
       trailing newline before reading input.
       """ ->
       function input(prompt::String="")::String
           print(prompt)
           return chomp(readline())
       end
input (generic function with 2 methods)

julia> x = parse(Int, input());
42

julia> typeof(ans)
Int64

julia> name = input("What is your name? ");
What is your name? Ismael

julia> typeof(name)
String

help?> input
search: input

  input(prompt::String="")::String

  Read a string from STDIN. The trailing newline is stripped.

  The prompt string, if given, is printed to standard output without a trailing newline before reading input.

julia>
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