节点请求抛出:错误:无效的URI"www.urlworksinbrowser.com"或options.uri是必需的参数

Question

我在Ubuntu 12.04上使用Node v0.10.11.我无法弄清楚我缺少什么来使URL流与请求模块一起工作.该程序试图访问邮件列表站点,找到每个月的下载链接,然后下载每个月的页面.

Mikael的自述文件说"第一个参数可以是url或options对象.唯一需要的选项是URI,其他所有选项都是可选的.ur || url - 完全限定的uri或url.parse()中解析的url对象"

如果我打电话url.parse(www.targeturl.com),我会

Error: options.uri is a required argument

如果我不使用url.parse,我会

Error: Invalid URI "www.freelists.org/archive/si-list/06-2013"

(此链接在我的浏览器中完美运行)

我把代码减少到了42行.欢迎任何建议

var request = require('request'),
  url = require('url'),
  stream = require('stream'),
  cheerio = require('cheerio'), // a reduced jQuery style DOM library
  Transform = require('stream').Transform

var DomStripStream = function(target) {
  this.target = target;
  stream.Transform.call(this,{objectMode: true});
}

DomStripStream.prototype = Object.create(
  Transform.prototype, {constructor: {value: DomStripStream}} 
)

DomStripStream.prototype.write = function () {
  this._transform.apply(this, arguments);
};

DomStripStream.prototype.end = function () {
  this._transform.apply(this, arguments);
  this.emit("end");
};

DomStripStream.prototype._transform = function(chunk, encoding, callback) {
  chunk = chunk ? chunk.toString() : "";
  $ = cheerio.load(chunk);
  domLinks = $(this.target);
  $(domLinks).each(function (i, link) {
    currLink = 'www.freelists.org' + $(link).attr('href') 
//  currLink = url.parse(currLink)
    request(currLink, function (error, response, body) {
      console.log(error);
    })
  });
}

var fs = require("fs"),
  output = fs.createWriteStream("out.txt"),
  mainPage = new DomStripStream('td a')

request('http://www.freelists.org/archive/si-list').
pipe(mainPage).
pipe(output);

Answer 1

在网址中添加http://或https://