JSP形成"行动"的价值观是什么？

Question

JSP表单行为可以做什么？我有一个Login.jsp页面供用户结束详细信息.我可以在表单操作中给出servlet类吗？

这是servlet代码.

package mybean;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;

public class LoginServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
public LoginServlet() {
    super();
}

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    try
    {
        System.out.println("In the Login Servlet");
        LoginBean user = new LoginBean();
        user.setUemail(request.getParameter("uemail"));
        user.setUpass(request.getParameter("upass"));
        user = LoginDAO.login(user);
        if(user.isValid())
        {
            HttpSession session = request.getSession(true);
            session.setAttribute("currentSessionUser",user);
            response.sendRedirect("LoginSuccess.jsp");
        }else
            response.sendRedirect("LoginFailed.jsp");
    } catch (Throwable exc)
    {
        System.out.println(exc);
    }
}

    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
}

}

Answer 1

根据规范,它可以采用任何有效的URI

此属性指定表单处理代理程序.未定义HTTP URI以外的值的用户代理行为.

我可以在表单操作中给出servlet类吗？

是,如果servlet类名解析为映射到的有效URL,web.xml否则您将遇到404.

那么让我们考虑一下你的JSP是应用程序的根

<FORM action="someServletName" method="post">

现在,这将被解析为protocol://servername:port/context/someServletName.现在您应该/someServletName在web.xml中或通过注释到Servlet或JSP 的映射.

<servlet>
     <servlet-name>someServletName</servlet-name>
     <servlet-path>packageName.servletName</servlet-path>
</servlet>
<servlet-mapping>
     <servlet-name>someServletName</servlet-name>
     <url-pattern>/someServletName</url-pattern>
</servlet-mapping>