Ath*_*ari 4 c# extensibility mef custom-attributes
我想导出类型 Foo具有多个元数据选项的:
public interface IFoo
{
void Do ();
}
[ExportFoo ("Bar", "1.0")]
[ExportFoo ("Baz", "1.0")]
[ExportFoo ("Baz", "2.0")]
public class Foo : IFoo
{
public void Do () {}
}
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我已经宣布了 ExportFooAttribute这样说了:
public interface IFooMeta
{
string Name { get; }
string Version { get; }
}
[MetadataAttribute, AttributeUsage (AttributeTargets.Class, AllowMultiple = true)]
public class ExportFooAttribute : ExportAttribute, IFooMeta
{
public string Name { get; private set; }
public string Version { get; private set; }
public ExportFooAttribute (string name, string version) : base(typeof(IFoo))
{
Name = name;
Version = version;
}
}
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根据文档,何时AllowMultiple设置为true,元数据实际上包含原始元数据的属性数组,所以我这样导入类型:
public interface IFooMultiMeta
{
string[] Name { get; }
string[] Version { get; }
}
public class Program
{
[ImportMany]
public List<Lazy<IFoo, IFooMultiMeta>> Foos { get; set; }
private static void Main ()
{
new Program().MainInternal();
}
private void MainInternal ()
{
new CompositionContainer(new AssemblyCatalog(Assembly.GetExecutingAssembly())).ComposeParts(this);
foreach (Lazy<IFoo, IFooMultiMeta> lazyFoo in Foos)
for (int i = 0; i < lazyFoo.Metadata.Name.Length; i++)
Console.WriteLine("* {0} {1}", lazyFoo.Metadata.Name[i], lazyFoo.Metadata.Version[i]);
Console.WriteLine(Equals(Foos[0].Metadata, Foos[1].Metadata));
Console.ReadKey();
}
}
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我希望得到一个实例 Foo包含元数据的其中包含3个值的数组.但是,我得到了这个:
* Baz 2.0
* Baz 1.0
* Bar 1.0
* Baz 2.0
* Baz 1.0
* Bar 1.0
* Baz 2.0
* Baz 1.0
* Bar 1.0
False
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更糟糕的是,元数据实例是不同的,所以我甚至无法正确筛选出重复项.
题:如何正确导出一个类以满足多个元数据属性组合?
这三个导出的原因是您从中导出自定义导出元数据 ExportAttribute.这意味着每个装饰都会发生不同的出口.三个装饰导致三个出口.
我不确定为什么每个导出都会获得所有{Name,Version}对.
要克服这三个导出,您可以更新自定义属性以从Attribute派生:
[MetadataAttribute, AttributeUsage (AttributeTargets.Class, AllowMultiple = true)]
public class ExportMetaFooAttribute : Attribute, IFooMeta
{
public string Name { get; private set; }
public string Version { get; private set; }
public ExportFooAttribute (string name, string version)
{
Name = name;
Version = version;
}
}
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我已将其重命名为,ExportMetaFooAttribute因为它不是导出属性,而是导出元数据属性.
然后你将你的Foo班级改为:
[Export(typeof(IFoo))]
[ExportMetaFoo("Bar", "1.0")]
[ExportMetaFoo("Baz", "1.0")]
[ExportMetaFoo("Baz", "2.0")]
public class Foo : IFoo
{
public void Do ()
{}
}
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正如您现在所看到的,我们需要额外的内容ExportAttribute来指定需要导出此类.