想在android中使用phonegap将图片上传到服务器

Question

想在android中使用phonegap将图片上传到服务器

Man*_*anu 14 android cordova

我在android phonegap做项目,我想上传pic到服务器.

但我不知道,我应该把这段代码放在哪里.

我无法显示任何上传照片的按钮,请帮忙.

我是新手.我从phonegap文档中查看了这段代码.

我想这几个小时,但无法得到更好的解决方案.

这是我的第一个android phonegap项目.

码:

   <head>
   <script type="text/javascript" charset="utf-8" src="cordova-2.4.0.js"></script>
   <script type="text/javascript" charset="utf-8">        
    document.addEventListener("deviceready", onDeviceReady, false);

    function onDeviceReady() {           
        navigator.camera.getPicture(uploadPhoto,
                function(message) { alert('get picture failed'); },
              { quality: 50, destinationType:    navigator.camera.DestinationType.FILE_URI,
                sourceType: navigator.camera.PictureSourceType.PHOTOLIBRARY }
             );
    }
    function uploadPhoto(imageURI) {
        var options = new FileUploadOptions();
        options.fileKey="file";
        options.fileName=imageURI.substr(imageURI.lastIndexOf('/')+1);
        options.mimeType="image/jpeg";

        var params = {};
        params.value1 = "test";
        params.value2 = "param";

        options.params = params;

        var ft = new FileTransfer();
        ft.upload(imageURI, encodeURI("http://some.server.com/upload.php"), win, fail, options);
    }

    function win(r) {
        console.log("Code = " + r.responseCode);
        console.log("Response = " + r.response);
        console.log("Sent = " + r.bytesSent);
    }

    function fail(error) {
        alert("An error has occurred: Code = " + error.code);
        console.log("upload error source " + error.source);
        console.log("upload error target " + error.target);
    }

    </script>
 </head>
 <body>
    <h1>Example</h1>
    <p>Upload File</p>
 </body>

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Answer 1

A. *_*ães 10

您可以使用下一个代码解决问题:

<script type="text/javascript">  
function uploadFromGallery() {

    // Retrieve image file location from specified source
    navigator.camera.getPicture(uploadPhoto,
                                function(message) { alert('get picture failed'); },
                                { quality: 50, 
                                destinationType: navigator.camera.DestinationType.FILE_URI,
                                sourceType: navigator.camera.PictureSourceType.PHOTOLIBRARY }
                                );

}

function uploadPhoto(imageURI) {
    var options = new FileUploadOptions();
    options.fileKey="file";
    options.fileName=imageURI.substr(imageURI.lastIndexOf('/')+1)+'.png';
    options.mimeType="text/plain";

    var params = new Object();

    options.params = params;

    var ft = new FileTransfer();
    ft.upload(imageURI, encodeURI("http://some.server.com/upload.php"), win, fail, options);
}

function win(r) {
    console.log("Code = " + r.responseCode);
    console.log("Response = " + r.response);
    console.log("Sent = " + r.bytesSent);
}

function fail(error) {
    alert("An error has occurred: Code = " + error.code);
    console.log("upload error source " + error.source);
    console.log("upload error target " + error.target);
}
</script>
</head>
<body>
   <a data-role="button" onClick="uploadFromGallery();">Upload from Gallery</a> 
</body>

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在这篇文章中查看更多信息:https: //stackoverflow.com/a/13862151/1853864

谢谢.它正确地解决了.但我们需要上传多张图片.请给我一个想法,使用此cordova文件传输上传多个图像. (2认同)

Answer 2

Amo*_*ane 5

请尝试以下代码.

// A button will call this function
// To capture photo
function capturePhoto() {
    // Take picture using device camera and retrieve image as base64-encoded string
    navigator.camera.getPicture(uploadPhoto, onFail, { 
        quality: 50, destinationType: Camera.DestinationType.FILE_URI 
    });
}

// A button will call this function
// To select image from gallery
function getPhoto(source) {
    // Retrieve image file location from specified source
    navigator.camera.getPicture(uploadPhoto, onFail, { quality: 50,
        destinationType: navigator.camera.DestinationType.FILE_URI,
        sourceType: navigator.camera.PictureSourceType.PHOTOLIBRARY
    });
}

function uploadPhoto(imageURI) {
    //If you wish to display image on your page in app
    // Get image handle
    var largeImage = document.getElementById('largeImage');

    // Unhide image elements
    largeImage.style.display = 'block';

    // Show the captured photo
    // The inline CSS rules are used to resize the image
    largeImage.src = imageURI;

    var options = new FileUploadOptions();
    options.fileKey = "file";
    var userid = '123456';
    var imagefilename = userid + Number(new Date()) + ".jpg";
    options.fileName = imagefilename;
    options.mimeType = "image/jpg";

    var params = new Object();
    params.imageURI = imageURI;
    params.userid = sessionStorage.loginuserid;
    options.params = params;
    options.chunkedMode = false;
    var ft = new FileTransfer();
    var url = "Your_Web_Service_URL";
    ft.upload(imageURI, url, win, fail, options, true);
}
//Success callback
function win(r) {
    alert("Image uploaded successfully!!");
}
//Failure callback
function fail(error) {
    alert("There was an error uploading image");
}
// Called if something bad happens.
// 
function onFail(message) {
    alert('Failed because: ' + message);
}

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在HTML页面中创建一个按钮,onclick根据您的要求在其上执行事件调用.

调用capturePhoto()捕获和上传照片的功能.
调用getPhoto()函数从图库中获取图像.

HTML应该包含如下按钮:

<input name="button" type="button" onclick="capturePhoto()" value="Take Photo"/>

<input name="button" type="button" onclick="getPhoto();" value="Browse" />

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希望有所帮助.

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