FragmentPagerAdapter getItem位置错误

Question

我有FramentPageAdapter的奇怪问题

MainActivity.java

@SuppressLint("ValidFragment")
public class MainActivity<DashboardActivity> extends FragmentActivity implements     ActionBar.TabListener {
...
...
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    final ActionBar actionBar = getActionBar();
    actionBar.setNavigationMode(ActionBar.NAVIGATION_MODE_TABS);
    mTabHost = (FragmentTabHost)findViewById(android.R.id.tabhost);
    mSectionsPagerAdapter = new SectionsPagerAdapter(getSupportFragmentManager());
    mViewPager = (ViewPager) findViewById(R.id.pager);
    mViewPager.setAdapter(mSectionsPagerAdapter);
    mViewPager.setOnPageChangeListener(new ViewPager.SimpleOnPageChangeListener() {
        @Override
        public void onPageSelected(int position) {
            actionBar.setSelectedNavigationItem(position);
        }
    });

    actionBar.addTab(actionBar.newTab().setText(mSectionsPagerAdapter.getPageTitle(0)).setTabListener(this).setIcon(R.drawable.rating_good));
    actionBar.addTab(actionBar.newTab().setText(mSectionsPagerAdapter.getPageTitle(1)).setTabListener(this).setIcon(R.drawable.action_search));
    actionBar.addTab(actionBar.newTab().setText(mSectionsPagerAdapter.getPageTitle(2)).setTabListener(this).setIcon(R.drawable.action_search));
}
...
public class SectionsPagerAdapter extends FragmentPagerAdapter {
    public SectionsPagerAdapter(FragmentManager fm) {
        super(fm);
    }
    public Fragment getItem(int position) {
        Fragment fragment = null; 
        switch(position) {
            case 0:
                fragment = new Fragment0();  
            break;
            case 1:
                fragment = new Fragment1();  
            break;
            case 2:
                fragment = new Fragment2();  
            break;
        }
        return fragment;
    }
    @Override
    public int getCount() {
        return 3;
    }
    /*
     * Title
     */
    @Override
    public CharSequence getPageTitle(int position) {
        Locale l = Locale.getDefault();
        switch (position) {
        case 0:
            return getString(R.string.title_section0).toUpperCase(l);
        case 1:
            return getString(R.string.title_section1).toUpperCase(l);
        case 2:
            return getString(R.string.title_section2).toUpperCase(l);
        }
        return null;
    }
}

当我尝试在3个选项卡之间切换时,public Fragment getItem(int position)返回错误的位置.当我用2个标签创建应用程序时,一切正常.添加超过2个,创建奇怪的问题.从0切换到1位置 - 工作正常,从1切换到0 - 工作正常,从1切换到2位置 - 工作正常,但是,当我尝试从2回到1位置时,public Fragment getItem(int position) - int position返回"0"而不是"1".有人帮我这个吗？

Answer 1

好的,我找到了解决方案.首先,getItem"int position"不表示当前的显示片段.要显示3个或更多选项卡,而不卸载firts片段您必须添加以下行:

mViewPager.setOffscreenPageLimit(3);

故事结局...