YET*_*ETI 12 java sql hibernate hibernate-mapping
1 2:select(table.*)/(all column)没问题
String sql = "select t_student.* from t_student";
//String sql = "select t_student.id,t_student.name,... from t_student"; //select all column
SQLQuery query = session.createSQLQuery(sql);
query.addEntity(Student.class);//or query.addEntity("alias", Student.class);
//query.list();[Student@..., Student@..., Student@...]
query.setResultTransformer(Transformers.ALIAS_TO_ENTITY_MAP); //or other transformer
query.list(); //[{Student(or alias)=Student@...},{Student=Student@...}]
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3:选择一些列(不是全部),是错误
String sql = "select t_student.id,t_student.name.t_student.sex from t_student";
SQLQuery query = session.createSQLQuery(sql);
query.addEntity(Student.class);
query.setResultTransformer(Transformers.ALIAS_TO_ENTITY_MAP);
query.list(); //Exception:invalid column/no column
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我希望"3"正常工作,并将结果映射到Student.class.
喜欢:学生[id =?,name =?,sex =?,(其他字段为null /默认)]
我不知道这个错误,请帮帮我!
Paw*_*iak 23
您可以进一步添加
.setResultTransformer(Transformers.aliasToBean(YOUR_DTO.class));
并自动将其映射到自定义dto对象,另请参阅返回非托管实体.
例如:
public List<MessageExtDto> getMessagesForProfile2(Long userProfileId) {
Query query = getSession().createSQLQuery(" "
+ " select a.*, b.* "
+ " from messageVO AS a "
+ " INNER JOIN ( SELECT max(id) AS id, count(*) AS count FROM messageVO GROUP BY messageConversation_id) as b ON a.id = b.id "
+ " where a.id > 0 "
+ " ")
.addScalar("id", new LongType())
.addScalar("message", new StringType())
......... your mappings
.setResultTransformer(Transformers.aliasToBean(MessageExtDto.class));
List<MessageExtDto> list = query.list();
return list;
}
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只有两种方法。
您可以使用第一个或第二个片段。根据 Hibernate 文档,您必须更喜欢第二个。
您可以只获取对象数组的列表,如下所示:
String sql = "select name, sex from t_student";
SQLQuery query = session.createSQLQuery(sql);
query.addScalar("name", StringType.INSTANCE);
query.addScalar("sex", StringType.INSTANCE);
query.list();
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