FOSUserBundle未在DoctrineFixtures中设置Salt

Question

我正在尝试将一些用户加载到我的数据库中,以便使用DoctrineFixturesBundle进行测试.我在StackOverflow上做了很多搜索,并且发现了很多其他问题.似乎没有我的答案.我正在加载我的用户使用FOS用户管理器.下面是我的夹具课程.

namespace Kandidly\UserBundle\DataFixtures;

use Doctrine\Common\DataFixtures\AbstractFixture;
use Doctrine\Common\DataFixtures\OrderedFixtureInterface;
use Doctrine\Common\Persistence\ObjectManager;
use Symfony\Component\DependencyInjection\ContainerAwareInterface;
use Symfony\Component\DependencyInjection\ContainerInterface;

class LoadUserData extends AbstractFixture implements OrderedFixtureInterface, ContainerAwareInterface
{
    private $container;

    /**
     * {@inheritDoc}
     */
    public function load(ObjectManager $manager)
    {
        $userManager = $this->container->get('fos_user.user_manager');

        $user1 = $userManager->createUser();
        $user1->setFirstName('Admin');
        $user1->setLastName('User');
        $user1->setCity('Somewhere');
        $user1->setState('TN');
        $user1->setUsername('admin');
        $user1->setEmail('admin@example.com');
        $user1->setPlainPassword('admin');
        $user1->setEnabled(true);
        $user1->setRoles(
            array(
                 'ROLE_ADMIN'
            )
        );

        $user2 = $userManager->createUser();
        $user2->setFirstName('Normal');
        $user2->setLastName('User');
        $user2->setCity('Another');
        $user2->setState('CA');
        $user2->setUsername('user');
        $user2->setEmail('use@example.com');
        $user2->setPlainPassword('user');
        $user2->setEnabled(true);
        $user2->setRoles(
            array(
                 'ROLE_USER'
            )
        );

        $userManager->updateUser($user1);
        $userManager->updateUser($user2);

        $this->addReference('admin-user', $user1);
    }

    /**
     * Get the order of this fixture
     *
     * @return integer
     */
    function getOrder()
    {
        return 1;
    }

    /**
     * Sets the Container.
     *
     * @param ContainerInterface|null $container A ContainerInterface instance or null
     *
     * @api
     */
    public function setContainer(ContainerInterface $container = null)
    {
        $this->container = $container;
    }
}

但是,当我运行灯具时,我得到一个错误,表示没有设置盐.有人可以帮忙吗？

Answer 1

猜猜你的用户类中有一个构造函数？因为salt是在基类User类的构造函数中设置的.

// FOS\UserBundle\Model\User

public function __construct()
{
    $this->salt = base_convert(sha1(uniqid(mt_rand(), true)), 16, 36);
    $this->enabled = false;
    $this->locked = false;
    $this->expired = false;
    $this->roles = array();
    $this->credentialsExpired = false;
}

如果你有自己的构造函数,不要忘记调用父构造函数parent::__construct()来使它工作.另请参见FOSUserBundle文档,其中提到了对父构造函数的调用.

从PHP文档:如果子类定义构造函数,则不会隐式调用父构造函数.为了运行父构造函数,需要在子构造函数中调用parent :: __ construct().如果子节点没有定义构造函数,那么它可以像普通类方法一样从父类继承(如果它没有被声明为私有).