Ale*_*oul 5 api video instagram
我在类似Facebook的社交网络上工作,需要从Instagram链接中提取mp4.
对于照片很简单: url_shared =" http://instagram.com/p/a69ygTTHKq/ "photo_to_embed = url_shared +"？size = t"
你知道类似的东西找到与mp4的直接链接吗？我尝试使用他们的API并将扩展名从".jpg"更改为".mp4",但由于它不能一直工作而失败.
例如:http:
//api.instagram.com/oembed？url = http://instagram.com/p/bCgbJ2pgCi/返回
{
provider_url: "http://instagram.com/",
media_id: "487094313204187298_9762431",
title: "So did you download our "Hockey Community" app yet? If you like hockey even just a bit you should do it now!!'",
url: "http://distilleryimage2.ak.instagram.com/d79af376deb011e2922a22000a1fdc29_7.jpg",
author_name: "hockeycommunity",
height: 612,
width: 612,
version: "1.0",
author_url: "http://instagram.com/hockeycommunity",
author_id: 9762431,
type: "photo",
provider_name: "Instagram"
}
data.url =" http://distilleryimage2.ak.instagram.com/d79af376deb011e2922a22000a1fdc29_ 7.jpg ",视频链接实际上是" http://distilleryimage2.ak.instagram.com/d79af376deb011e2922a22000a1fdc29_ 101.mp4 "
只有文件名的末尾发生变化,但无法弄清楚规则是什么......
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