在一个sql命令访问中从一个数据库表中选择多个计数

Question

我有一个以下格式的表格：

STATE SURVEY_ANSWER  
NC high  
NC moderate  
WA high  
FL low  
NC high

我正在寻找一个可以得到以下结果的查询：

STATE HIGH MODERATE LOW 
NC 2 1 0  
WA 1 0 0  
FL 0 0 1

不幸的是，这些是我得到的结果：

STATE HIGH MODERATE LOW 
NC 3 1 1  
WA 3 1 1  
FL 3 1 1  

这是我正在使用的代码：

Select mytable.STATE,
(SELECT COUNT(*) FROM mytable WHERE mytable.survey_answer = 'low' and state = mytable.state) AS low,
(SELECT COUNT(*) FROM mytable WHERE mytable.survey_answer = 'moderate' and state = mytable.state) AS moderate,
(SELECT COUNT(*) FROM mytable WHERE mytable.survey_answer = 'high' and state = mytable.state) AS high,
FROM mytable
GROUP BY mytable.state;

虽然这个论坛和其他论坛非常有帮助，但我无法弄清楚我做错了什么。请注意：我正在使用 Access，所以 CASE WHEN 解决方案不起作用。谢谢你的任何建议。

Answer 1

看起来这可能是不使用表别名导致的问题。因为您正在对外部SELECT正在使用的同一个表进行子查询，并且没有给外部表一个别名，WHERE所以子查询中的两个条件都只使用子查询中的数据。

换句话说，当你写：

SELECT COUNT(*) FROM mytable WHERE mytable.survey_answer = 'low' and state = mytable.state

它对外部查询一无所知。

尝试这个：

SELECT t1.STATE,
  (SELECT COUNT(*) FROM mytable t2 WHERE t2.state = t1.state AND t2.survey_answer = 'low') low,
  (SELECT COUNT(*) FROM mytable t3 WHERE t3.state = t1.state AND t3.survey_answer = 'moderate') moderate,
  (SELECT COUNT(*) FROM mytable t4 WHERE t4.state = t1.state AND t4.survey_answer = 'high') high,
FROM mytable t1
GROUP BY t1.state