Laravel 4中的Laravel-Oauth2问题

Question

我使用laravel-oauth2包为Laravel 4设置Facebook登录.我正在使用这里看到的包:https: //github.com/madewithlove/laravel-oauth2

当运行控制登录的页面,public/oauth/facebook时,Facebook提示正常,但当我点击"接受"时,该页面会出现以下错误:

ErrorException
Argument 1 passed to OAuth2\Provider\Facebook::get_user_info() must be an instance of OAuth2\Token\Token_Access, instance of OAuth2\Token_Access given, called in /Applications/MAMP/htdocs/crowdsets/laravel-master/app/controllers/Oauth2Controller.php on line 36 and defined

它指向 /­vendor/­taylorotwell/­laravel-oauth2/­src/­OAuth2/­Provider/­Facebook.php: 26

get_user_info()Facebook.php中的功能如下所示:

public function get_user_info(Token_Access $token)
    {
        $url = 'https://graph.facebook.com/me?'.http_build_query(array(
            'access_token' => $token->access_token,
        ));

        $user = json_decode(file_get_contents($url));

        // Create a response from the request
        return array(
            'uid' => $user->id,
            'nickname' => $user->username,
            'name' => $user->name,
            'email' => $user->email,
            'location' => $user->hometown->name,
            'description' => $user->bio,
            'image' => 'https://graph.facebook.com/me/picture?type=normal&access_token='.$token->access_token,
            'urls' => array(
              'Facebook' => $user->link,
            ),
        );
    }

我的Oauth2Controller.php文件如下所示:

<?php 

    use OAuth2\OAuth2;
    use OAuth2\Token_Access;
    use OAuth2\Exception as OAuth2_Exception;

class Oauth2Controller extends BaseController
{



    public function getIndex($provider) {


        $provider = OAuth2::provider($provider, array(
        'id' => '****************',
        'secret' => '********************',
        ));

        if(! isset($_GET['code'])) {

            return $provider->authorize();

        }

        else
    {
        // Howzit?
        try
        {
            $params = $provider->access($_GET['code']);

                $token = new Token_Access(array(
                    'access_token' => $params->access_token
                ));
                $user = $provider->get_user_info($token);

            // Here you should use this information to A) look for a user B) help a new user sign up with existing data.
            // If you store it all in a cookie and redirect to a registration page this is crazy-simple.
            echo "<pre>";
            var_dump($user);
        }

        catch (OAuth2_Exception $e)
        {
            show_error('That didnt work: '.$e);
        }
    }

    }


}

我不知道为什么它会给我这个错误,因为我遵循了文档和教程.感谢您帮助解决此问题.

Answer 1

我研究了包的源代码,它似乎是Facebook提供商的错误(实际上大多数提供商)

例如,在Facebook提供商的开头,它执行此操作:

<?php

use OAuth2\Token\Token_Access;

OAuth2\Token命名空间中实际上没有类.但是,OAuth2名称空间中有一个.所以用上面的值替换上面的值

<?php

use OAuth2\Token_Access;

应该修复你的错误.您应该为所有提供商执行此操作.

PSR命名空间标准规定了下划线到目录的映射.因此OAuth\Token_Access通常会在./OAuth/Token/Access.php文件中查找类