“过滤” JSON以获取唯一键并获取所有相关值

Question

用组找到所有可能的相关值的最佳方法是什么。

var table = [
    {group:"a", stuff:"new"},
    {group:"a", stuff:"old"},
    {group:"b", stuff:"newOld"},
    {group:"b", stuff:"old"},
    {group:"c", stuff:"new"},
    {group:"c", stuff:"old"},
    {group:"c", stuff:"newOld"},
];

我想填充一个包含唯一group值的下拉列表。在选择时，我想将所有相关内容stuff用于进一步处理。并且还想添加一个包含all的组stuff。例如

on selection of all -> new, old, newOld
                a -> new, old
                b -> newOld, old
                c -> new, old, newOld

Answer 1

简短而精确，没有在整个数组中每次查找条目的开销：

var groups = {all:{}};
table.forEach(function(a){
    if (!groups[a.group]){ groups[a.group] = {}; }
    groups[a.group][a.stuff] = groups["all"][a.stuff] = 1;
});

列出对象中的内容，这样就没有重复的条目（这就是为什么很多余的原因=1）。但是您可以轻松地扩展它以计算重复项：

table.forEach(function(a){
    if (!groups[a.group]){ groups[a.group] = {}; }
    var stuff = groups["all"][a.stuff];
    groups["all"][a.stuff] = !stuff ? 1 : ++stuff;
    stuff = groups[a.group][a.stuff];
    groups[a.group][a.stuff] = !stuff ? 1 : ++stuff;
});

结果将如下所示：

// "groups" holds all group elements and their stuff values
groups = { "all": {"new":2,"old":3,"newOld":2},
           "a" : {"new":1,"old":1},
           "b" : {"newOld":1,"old":1},
           "c" : {"new":1,"old":1,"newOld":1}
         }

要检索组的值，只需说：

var groupname = "a"; // whatever group you need
Object.keys(groups[groupname]);
// will give you:
["new","old"]

演示版

^{得注意的支持Object.keys和Array.prototype.forEach课程。}