用PHP阅读电子邮件

Jac*_*ish 4 php regex database email

我需要从中读取字段 email

MOVE INFORMATION

Pickup Address: 34 Marigold Ln, Marlboro, NJ 07746

Delivery Address: 180 Prospect Park W, Apt 5, Brooklyn, NY 11215

Primary service dates:
Pack Date: N/A
Move Date: 6/6/2013

Other service dates:
Pack Date 2: N/A
Move Date2: N/A
Other Date: N/A
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我遵循的流程是:

  1. 通过IMAP连接
  2. 得到nessage身体

现在我想读取指定的数据,需要将其转换为数组,如:

array( ' Pickup Address'=>'34 Marigold Ln, Marlboro, NJ 07746', 
       'Delivery Address'=>'180 Prospect Park W, Apt 5, Brooklyn, NY 11215'...)
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我试过了 preg_match('/(?P<Pickup Address>\w+): (?P<Delivery Address>\d+)/', $body, $matches)

但那有一些问题:

  1. 在"取件地址"中不接受空格
  2. 它以Array ( [0] => Address: 34 [PickupAddress] => Address [1] => Address [DeliveryAddress] => 34 [2] => 34 )格式提供数组.

基本上我需要在数据库中保存这些字段,我不能在这里使用附件.如果您有任何其他解决方案或任何方式使其工作,请告诉我

Ham*_*mZa 5

像这样的东西?

$string = 'MOVE INFORMATION

Pickup Address: 34 Marigold Ln, Marlboro, NJ 07746

Delivery Address: 180 Prospect Park W, Apt 5, Brooklyn, NY 11215

Primary service dates:
Pack Date: N/A
Move Date: 6/6/2013

Other service dates:
Pack Date 2: N/A
Move Date2: N/A
Other Date: N/A';

preg_match_all('#(.*?):(.*)#m', $string, $m);
if(isset($m[1], $m[2])){
    $array = array_combine($m[1], $m[2]);
    print_r($array);
}
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输出:

Array
(
    [Pickup Address] =>  34 Marigold Ln, Marlboro, NJ 07746
    [Delivery Address] =>  180 Prospect Park W, Apt 5, Brooklyn, NY 11215
    [Primary service dates] => 
    [Pack Date] =>  N/A
    [Move Date] =>  6/6/2013
    [Other service dates] => 
    [Pack Date 2] =>  N/A
    [Move Date2] =>  N/A
    [Other Date] =>  N/A
)
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