Jac*_*ish 4 php regex database email
我需要从中读取字段 email
MOVE INFORMATION
Pickup Address: 34 Marigold Ln, Marlboro, NJ 07746
Delivery Address: 180 Prospect Park W, Apt 5, Brooklyn, NY 11215
Primary service dates:
Pack Date: N/A
Move Date: 6/6/2013
Other service dates:
Pack Date 2: N/A
Move Date2: N/A
Other Date: N/A
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我遵循的流程是:
现在我想读取指定的数据,需要将其转换为数组,如:
array( ' Pickup Address'=>'34 Marigold Ln, Marlboro, NJ 07746',
'Delivery Address'=>'180 Prospect Park W, Apt 5, Brooklyn, NY 11215'...)
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我试过了 preg_match('/(?P<Pickup Address>\w+): (?P<Delivery Address>\d+)/', $body, $matches)
但那有一些问题:
Array ( [0] => Address: 34 [PickupAddress] => Address [1] => Address [DeliveryAddress] => 34 [2] => 34 )
格式提供数组.基本上我需要在数据库中保存这些字段,我不能在这里使用附件.如果您有任何其他解决方案或任何方式使其工作,请告诉我
像这样的东西?
$string = 'MOVE INFORMATION
Pickup Address: 34 Marigold Ln, Marlboro, NJ 07746
Delivery Address: 180 Prospect Park W, Apt 5, Brooklyn, NY 11215
Primary service dates:
Pack Date: N/A
Move Date: 6/6/2013
Other service dates:
Pack Date 2: N/A
Move Date2: N/A
Other Date: N/A';
preg_match_all('#(.*?):(.*)#m', $string, $m);
if(isset($m[1], $m[2])){
$array = array_combine($m[1], $m[2]);
print_r($array);
}
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输出:
Array
(
[Pickup Address] => 34 Marigold Ln, Marlboro, NJ 07746
[Delivery Address] => 180 Prospect Park W, Apt 5, Brooklyn, NY 11215
[Primary service dates] =>
[Pack Date] => N/A
[Move Date] => 6/6/2013
[Other service dates] =>
[Pack Date 2] => N/A
[Move Date2] => N/A
[Other Date] => N/A
)
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