Wal*_*cio 4 xml r google-maps-api-3 driving-distance
假设平均速度为65 km/h,我使用以下函数估算行驶一定距离的时间(以小时为单位):
distHoras <- function(origin, destination){
xml.url <- paste0('http://maps.googleapis.com/maps/api/distancematrix/xml?origins=',
origin, '&destinations=', destination, '&mode=driving&sensor=false')
xmlfile <- xmlParse(getURL(xml.url))
dist <- xmlValue(xmlChildren(xpathApply(xmlfile,"//distance")[[1]])$value)
distance <- as.numeric(sub(" km", "", dist))
time <- (distance / 1000) / 65
return(time)
}
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我如何调整此函数以使其直接产生时间,因此我不需要进行65 km/h的假设,从而得到更好的估计?阅读文档后,我尝试将'distance'切换为'duration',但它没有用.我可能错过了一些简单的东西,但我对使用API很新,并且被所有文本所淹没.感谢任何帮助!
你在找这个:
library(ggmap)
from <- 'Paris'
to <- 'London'
mapdist(from,to,mode='driving')
from to m km miles seconds minutes hours
1 Paris London 454416 454.416 282.3741 18283 304.7167 5.078611
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mapdist使用Google地图计算地图距离.
为了回答你的问题,我认为使用json版本的谷歌API比使用谷歌API更容易(甚至推荐).
这里有一个快速版本RJSONIO.即使我建议你使用上面的功能.无需进行任何转换,因为结果已经是几小时.
library(RJSONIO)
distHoras <- function(origin, destinations){
origin <- gsub(",", "", origin)
origin <- gsub(" ", "+", origin)
origin <- paste("origins=", origin, sep = "")
destinations <- gsub(",", "", destinations)
destinations <- gsub(" ", "+", destinations)
destinations <- paste("destinations=", paste(destinations,
collapse = "|"), sep = "")
mode4url <- paste("mode=", 'driving', sep = "")
lang4url <- paste("language=", 'en-EN', sep = "")
sensor4url <- paste("sensor=", tolower(as.character(FALSE)),
sep = "")
posturl <- paste(origin, destinations, mode4url, sensor4url,
sep = "&")
url_string <- paste("http://maps.googleapis.com/maps/api/distancematrix/json?",
posturl, sep = "")
url_string <- URLencode(url_string)
connect <- url(url_string)
tree <- fromJSON(paste(readLines(connect), collapse = ""))
close(connect)
rapply(tree$rows,I)
}
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现在你测试它:
distHoras('Paris','London')
elements.distance.text elements.distance.value elements.duration.text
"454 km" "454416" "5 hours 5 mins"
elements.duration.value elements.status
"18283" "OK"
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