按ID大小获取图像源

Question

我正在使用一些促销/广告滑块与WP Analytics点击事件在WP网站上工作.效果很好,现在我想在正确的分辨率上提供正确的图像.

我正在使用picturefill来提供图像.硬编码时工作正常,所以我知道它有效.当我试图获取WP上传的图像的图像源时没有.我知道这是因为我的(缺乏)PHP技能.

图片需要什么:

<span data-picture data-alt="">
    <span data-src="filename_default.jpg"></span>
    <span data-src="filename_small.jpg" data-media="(min-width: 400px)"></span>
    <span data-src="filename_medium.jpg" data-media="(min-width: 768px)"></span>
    <span data-src="filename_big.jpg" data-media="(min-width: 1200px)"></span>

    <!-- Fallback content for non-JS browsers. -->
    <noscript>
        <img src="external/imgs/small.jpg" alt="">
    </noscript>
</span>

我有url或id或图像存储在:$ attachment_id

我以为这样做:

<?php
    $attachment_id = get_field('advimg');
    $large = "adv-pos-a-large";
    $default = "adv-pos-a-default";
    $small = "adv-pos-a-small";

?>

所述get_field( 'advimg'); 来自ACF.

<span data-picture data-alt="">
    <span data-src="<?php wp_get_attachment_image_src( $attachment_id, $default ); ?>"></span>
    <span data-src="<?php wp_get_attachment_image_src( $attachment_id, $small ); ?>" data-media="(min-width: 400px)"></span>
    <span data-src="<?php wp_get_attachment_image_src( $attachment_id, $default ); ?>" data-media="(min-width: 768px)"></span>
    <span data-src="<?php wp_get_attachment_image_src( $attachment_id, $large ); ?>" data-media="(min-width: 1200px)"></span>

    <!-- Fallback content for non-JS browsers. -->
    <noscript>
        <img src="external/imgs/small.jpg" alt="">
    </noscript>
</span>

但它没有用.我玩过:

wp_get_attachment_image_src wp_get_attachment_image_url wp_get_attachment_image_link

我必须有星期五,因为它没有工作,有些东西对我说,这不是那么难......我今天才看到它.

希望你们能投入其中.

提前致谢,

/保罗

编辑/最终代码/修复

<?php 
    $attachment_id = get_field('advanced_custom_field_name_here');
    $small = wp_get_attachment_image_src( $attachment_id, 'adv-pos-a-small' );
    $default = wp_get_attachment_image_src( $attachment_id, 'adv-pos-a-default' );
    $large = wp_get_attachment_image_src( $attachment_id, 'adv-pos-a-large' );
?> 

<span data-picture data-alt="alt desc here">
    <span data-src="<?php echo $default[0]; ?>"></span>
    <span data-src="<?php echo $small[0]; ?>" data-media="(min-width: 400px)"></span>
    <span data-src="<?php echo $default[0]; ?>" data-media="(min-width: 768px)"></span>
    <span data-src="<?php echo $large[0]; ?>" data-media="(min-width: 1200px)"></span>

    <!-- Fallback content for non-JS browsers. Same img src as the initial, unqualified source element. -->
    <noscript>
        <img src="<?php echo $default[0]; ?>" alt="alt desc here">
    </noscript>
</span>

Answer 1

wp_get_attachment_image_src令人困惑的名字.(更好的名称是wp_get_attachment_image_atts).它实际上返回一个图像附件文件的图像属性"url","width"和"height"的数组.对于图像src,使用返回数组中的第一个元素:

$img_atts = wp_get_attachment_image_src( $attachment_id, $default );
$img_src = $img_atts[0];

此外,请确保将ACF图像字段返回类型设置为附件ID,以便$attachment_id = get_field('advimg');为您提供所需的ID.