为什么从闭包中抛出我的异常没被捕获？

Question

我编写了一个PHPUnit测试,用于检查调用方法时是否从闭包中抛出异常.闭包函数作为参数传递给方法,并从中抛出异常.

public function testExceptionThrownFromClosure()
{
    try {
        $this->_externalResourceTemplate->get(
            $this->_expectedUrl,
            $this->_paramsOne,
            function ($anything) {
                throw new Some_Exception('message');
            }
        );

        $this->fail("Expected exception has not been found");
    } catch (Some_Exception $e) {
        var_dump($e->getMessage()); die;
    }
}

在ExternalResourceTemplate上指定的get函数的代码是

public function get($url, $params, $closure)
{
    try {
        $this->_getHttpClient()->setUri($url);
        foreach ($params as $key => $value) {
            $this->_getHttpClient()->setParameterGet($key, $value);
        }
        $response = $this->_getHttpClient()->request();
        return $closure($response->getBody());
    } catch (Exception $e) {
        //Log
        //Monitor
    }
}

有关为什么会调用fail assert语句的任何想法？你能不能捕获PHP中从闭包中抛出的异常,或者是否有一种我不知道的特定方式来处理它们.

对我来说,异常应该只是传播出返回堆栈,但它似乎没有.这是一个错误吗？仅供参考我正在运行PHP 5.3.3

Answer 1

感谢您的回答...

设法找出问题所在。看起来问题在于正在调用的 try-catch 块就是调用闭包的块。这是有道理的...

所以上面的代码应该是

public function get($url, $params, $closure)
{
    try {
        $this->_getHttpClient()->setUri($url);
        foreach ($params as $key => $value) {
            $this->_getHttpClient()->setParameterGet($key, $value);
        }
        $response = $this->_getHttpClient()->request();
        return $closure($response->getBody());
    } catch (Exception $e) {
        //Log
        //Monitor
        throw new Some_Specific_Exception("Exception is actually caught here");
    }
}

所以看起来 PHP 5.3.3 并没有提到的 bug。我的错。