PHP cURL GET请求和请求的正文

Question

我正在尝试使用cURL来获取这样的GET请求:

function connect($id_user){
    $ch = curl_init();
    $headers = array(
    'Accept: application/json',
    'Content-Type: application/json',

    );
    curl_setopt($ch, CURLOPT_URL, $this->service_url.'user/'.$id_user);
    curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
    curl_setopt($ch, CURLOPT_HEADER, 0);
    $body = '{}';

    curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "GET"); 
    curl_setopt($ch, CURLOPT_POSTFIELDS,$body);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

    // Timeout in seconds
    curl_setopt($ch, CURLOPT_TIMEOUT, 30);

    $authToken = curl_exec($ch);

    return $authToken;
}

当你看到我想传递$ body作为请求的正文,但我不知道它是否正确而我实际上无法调试,你知道是否有权使用 curl_setopt($ch, CURLOPT_POSTFIELDS,$body);GET请求吗？

因为这个enteire代码与POST完美配合,现在我正在尝试将此更改为GET,如您所见

Answer 1

接受的答案是错误的.GET请求确实可以包含一个正文.这是WordPress实现的解决方案,例如:

curl_setopt( $ch, CURLOPT_CUSTOMREQUEST, 'GET' );
curl_setopt( $ch, CURLOPT_POSTFIELDS, $body );

编辑:为了澄清,curl_setopt在这种情况下,初始是没有必要的,但没有伤害.包含它是为了充分说明所引用的示例代码.

Answer 2

CURLOPT_POSTFIELDS顾名思义,是针对POST请求的正文(有效负载).对于GET请求,有效负载是查询字符串形式的URL的一部分.

在您的情况下,您需要使用您需要发送的参数(如果有)构造URL,并删除cURL的其他选项.

curl_setopt($ch, CURLOPT_URL, $this->service_url.'user/'.$id_user);
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
curl_setopt($ch, CURLOPT_HEADER, 0);

//$body = '{}';
//curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "GET"); 
//curl_setopt($ch, CURLOPT_POSTFIELDS,$body);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

Answer 3

  <?php
  $post = ['batch_id'=> "2"];
  $ch = curl_init();
  curl_setopt($ch, CURLOPT_URL,'https://example.com/student_list.php');
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
  curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($post));
  $response = curl_exec($ch);
  $result = json_decode($response);
  curl_close($ch); // Close the connection
  $new=   $result->status;
  if( $new =="1")
  {
    echo "<script>alert('Student list')</script>";
  }
  else 
  {
    echo "<script>alert('Not Removed')</script>";
  }

  ?>