我已经读过这个问题:更改集合中的元素会改变'equals'语义
但是,我不知道如何解决我无法更改HashSet中的项目并在以后删除它的问题.
我有一些示例源代码:
public static void main(String[] args) {
TestClass testElement = new TestClass("1");
Set<TestClass> set = new HashSet<>();
set.add(testElement);
printIt(testElement, set, "First Set");
testElement.setS1("asdf");
printIt(testElement, set, "Set after changing value");
set.remove(testElement);
printIt(testElement, set, "Set after trying to remove value");
testElement.setS1("1");
printIt(testElement, set, "Set after changing value back");
set.remove(testElement);
printIt(testElement, set, "Set removing value");
}
private static void printIt(TestClass hullo, Set<TestClass> set, String message) {
System.out.println(message + " (hashCode is " + hullo.hashCode() + "):");
for (TestClass testClass : set) {
System.out.println(" " + testClass.toString());
System.out.println(" HashCode: " + testClass.hashCode());
System.out.println(" Element is equal: " + hullo.equals(testClass));
}
}
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其中TestClass只是一个包含变量(加上getter和setter)并且实现了hashcode()和equals()的POJO.
有一个请求显示equals()和hashcode() - 方法.这些是由eclipse自动生成的:
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + ((s1 == null) ? 0 : s1.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
TestClass other = (TestClass) obj;
if (s1 == null) {
if (other.s1 != null)
return false;
} else if (!s1.equals(other.s1))
return false;
return true;
}
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结果如下:
First Set (hashCode is 80):
TestClass [s1=1]
HashCode: 80
Element is equal: true
Set after changing value (hashCode is 3003475):
TestClass [s1=asdf]
HashCode: 3003475
Element is equal: true
Set after trying to remove value (hashCode is 3003475):
TestClass [s1=asdf]
HashCode: 3003475
Element is equal: true
Set after changing value back (hashCode is 80):
TestClass [s1=1]
HashCode: 80
Element is equal: true
Set removing value (hashCode is 80):
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当哈希码发生变化时,我无法从HashSet中删除该值.在链接的问题中,我理解为什么会这样,但我不知道如何删除更改的值.有没有可能这样做?
您遇到了问题,因为哈希集中的键不是不可变的.如果您没有不可变密钥,则修改后将丢失原始密钥对象的引用.并且永远无法处理它,有时也称为集合中的内存泄漏.因此,如果您使用不可变密钥,则不会遇到这种情况.
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