使用spring webservice模板的原始xml响应

Man*_*esh 5 spring

我正在编写一个客户端,使用webserviceTemplate(spring-ws)调用SOAP webservice.我正在使用JAXB将wsdl转换为POJO.我将请求作为POJO发送到webservice但是想要以xml格式的响应(原始xml而不是unmarshalled pojo格式).

wsTemplate.marshalSendAndReceive(requestPayload)会给我unmarshalled pojo对象作为输出但是我需要原始xml来响应webservice调用.

还有一个查询,如果我将响应作为原始xml,我仍然需要将marshaller bean定义为:

<bean id="messageFactory" class="org.springframework.ws.soap.saaj.SaajSoapMessageFactory"/>

<bean id="marshaller" class="org.springframework.oxm.jaxb.Jaxb2Marshaller">
    <property name="contextPath" value="com.abc.xyz" />
</bean>
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(当我定义这个编组,我得到误差不能编组型"com.abc.xyz.GetAbc"为元素,因为它缺少一个@XmlRootElement注释])

任何帮助.

Bet*_*sta 5

对您来说可能为时已晚,但是可以将POJO编组回XML,可以使用

final Result marshallerResult = new StringResult();
marshaller.marshal(input, marshallerResult);
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marshaller您在哪里使用过的那个wsTemplate

<bean id="marshaller" class="org.springframework.oxm.jaxb.Jaxb2Marshaller">
    <property name="contextPath" value="com.dhl.dctservice" />
</bean>

<bean id="webServiceTemplate" class="org.springframework.ws.client.core.WebServiceTemplate">     
    <property name="marshaller" ref="marshaller" />
    <property name="unmarshaller" ref="marshaller" />
</bean>
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StringResult来自org.springframework.xml.transform包装。

要从WSDL生成POJO,我正在使用Maven插件

<!-- WSDL -> Java (start) -->
<plugin>
    <!-- !!! READ !!! -->
    <!-- mvn cxf-codegen-plugin:wsdl2java NOT working, comment phase and
    run "mvn clean install -DskipTests") -->
    <groupId>org.apache.cxf</groupId>
    <artifactId>cxf-codegen-plugin</artifactId>
    <version>${cxf-codegen-plugin.version}</version>
    <executions>
        <execution>
            <id>wsdl2java</id>
            <!-- comment this to generate java classes from wsdl during the "mvn
            clean install -DskipTests" -->
            <phase>manual-generate-sources</phase>
            <configuration>
                <wsdlOptions>
                    <wsdlOption>
                        <wsdl>${basedir}/src/main/resources/wsdl/service.wsdl</wsdl>
                        <extraargs>
                            <extraarg>-verbose</extraarg>
                            <extraarg>-b</extraarg>
                            <extraarg>${basedir}/src/main/resources/wsdl/bindings.xml</extraarg>
                            <extraarg>-client</extraarg>
                            <extraarg>-xjc-Xts</extraarg>
                        </extraargs>
                    </wsdlOption>
                </wsdlOptions>
            </configuration>
            <goals>
                <goal>wsdl2java</goal>
            </goals>
        </execution>
    </executions>
    <dependencies>
        <dependency>
            <groupId>org.codehaus.woodstox</groupId>
            <artifactId>stax2-api</artifactId>
            <version>3.1.1</version>
        </dependency>
        <dependency>
            <groupId>org.apache.cxf</groupId>
            <artifactId>cxf-xjc-ts</artifactId>
            <version>2.2.12</version>
        </dependency>
        <dependency>
            <groupId>org.jvnet.jaxb2_commons</groupId>
            <artifactId>jaxb2-basics-jaxb-xjc</artifactId>
            <version>2.1.13</version>
        </dependency>
    </dependencies>
</plugin>
<!-- WSDL -> Java (end) -->
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binding.xml文件在哪里

<jaxb:bindings
    version="2.1" 
    xmlns:jaxb="http://java.sun.com/xml/ns/jaxb" 
    xmlns:xjc="http://java.sun.com/xml/ns/jaxb/xjc" 
    xmlns:xs="http://www.w3.org/2001/XMLSchema"> 

    <jaxb:globalBindings generateElementProperty="false">
        <xjc:simple />
    </jaxb:globalBindings>

</jaxb:bindings>
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  • 已支持,但是:我正在阅读本文的原因是,我想存储传入的XML以解决将来与外部源的潜在纠纷。因此,如果有任何编码/排序差异,我想在解组之前精确地获取字节。 (3认同)