值'0000-00-00'不能表示为java.sql.Date

jav*_*ser 11 java mysql hibernate spring-mvc java.util.date

我正在研究一些需要从数据库中提取数据的项目,我使用Spring MVC从DB构建模型来选择数据.

这是我的JSP页面的问题:

<form action="result" method="get" >
<table>
<thead>
<tr>
<th>Date to select:</th>
<th>Name to select:</th>
<th>Type to select:</th>
</tr>
</thead>

<tbody>
<tr>
<td><form:select  path="listOfDates">
<form:option value="NONE"> --SELECT--</form:option>
<form:options items="${listOfDates}"></form:options>
</form:select>
</td>  
<td><form:select  path="listOfInstitutionsNames">
<form:option value="NONE"> --SELECT--</form:option>
<form:options items="${listOfInstitutionsNames}"></form:options>
</form:select>
</td>
<td>
<form:select  path="listOfInstitutionsTypes">
<form:option value="NONE"> --SELECT--</form:option>
<form:options items="${listOfInstitutionsTypes}"></form:options>
</form:select>
</td>
</tr>
</tbody>

<tfoot>
<tr>
<td><input type="submit" value="???????"/></td>
</tr>
</tfoot>

</table>
</form>
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正如你可以看到我尝试使用<form:select>Spring标签库.
问题:
但是当它用这个控制器准备我的模型时:

@Controller
public class HomeController{ 

    @Autowired
    private ControllerSupportClass controllerSupportClass; 


        @RequestMapping(value="/search", method=RequestMethod.GET)
        public String search(Model model) {
            List<Date> listOfDates = controllerSupportClass.findAllDatesForm();
            List<String> listOfInstitutionsNames = controllerSupportClass.findAllInstitutionsForm();
            List<String> listOfInstitutionsTypes = controllerSupportClass.findAllTypesForm();
            model.addAttribute("listOfInstitutionsTypes", listOfInstitutionsTypes);
            model.addAttribute("listOfInstitutionsNames", listOfInstitutionsNames);
            model.addAttribute("listOfDates", listOfDates);
            return "search";    
        }


        @RequestMapping(value ="/result", method=RequestMethod.GET)
        public String SecondActionPage(@RequestParam String particularDate, 
                                       @RequestParam String nameOfInstitution, 
                                       @RequestParam String typeName,
                                       Model model) throws Exception {


                if(particularDate !="" && nameOfInstitution.trim() !="" && typeName.trim()=="") {                   
                    controllerSupportClass.findWithDateAndName(nameOfInstitution, particularDate, model);                   
                } else if(particularDate.trim() !="" && nameOfInstitution.trim() =="" && typeName.trim() !="") {                    
                    controllerSupportClass.findWithAddedDateAndType(typeName, particularDate, model);                   
                } else if(particularDate.trim() !="" && nameOfInstitution.trim() =="" && typeName.trim() ==""){         
                    controllerSupportClass.findWithAddedDate(particularDate, model);    
                } else if(particularDate.trim() !="" && nameOfInstitution.trim() !="" && typeName.trim() !="") {
                    throw new Exception("Search by choose all parameters is not exceptable");   
                } else {    
                    throw new Exception("You didn't put any search parameters");    
                }           
            return "search";
        }

}
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它给我一个这样的错误:

WARN : org.springframework.web.servlet.PageNotFound - No mapping found for HTTP request with URI [/controller/] in DispatcherServlet with name 'appServlet' Hibernate: select distinct creationda0_.DATE_ID as DATE1_0_, creationda0_.CHILD_ADMISSION_DATE as CHILD2_0_, creationda0_.CHILD_GO_SCHOOL_DATE as CHILD3_0_, creationda0_.PARTICULAR_DATE as PARTICULAR4_0_, creationda0_.VERSION as VERSION0_ from CREATION_DATE creationda0_ WARN : org.hibernate.util.JDBCExceptionReporter - SQL Error: 0, SQLState: S1009 ERROR: org.hibernate.util.JDBCExceptionReporter - Value '0000-00-00' can not be represented as java.sql.Date Jun 19, 2013 3:26:53 PM org.apache.catalina.core.StandardWrapperValve invoke SEVERE: Servlet.service() for servlet [appServlet] in context with path [/controller] threw exception [Request processing failed; nested exception is org.hibernate.exception.GenericJDBCException: could not execute query] with root cause java.sql.SQLException: Value '0000-00-00' can not be represented as java.sql.Date

If you need my Entity class it's here I'm using Date from java.util, but I go with @Temporal annotation to convert it from SQL to unit Date as I understand:

@Entity
@Table(name="CREATION_DATE")
public class CreationDate implements Serializable {


    private int dateId;

        @Id
        @GeneratedValue(strategy=IDENTITY)
        @Column(name="DATE_ID")
        public int getDateId() {
            return dateId;
        }

        public void setDateId(int dateId) {
            this.dateId = dateId;
        }


    private int version;

        @Version
        @Column(name="VERSION")
        public int getVersion() {
            return version;
        }

        public void setVersion(int version) {
            this.version = version;
        }


    private Date particularDate;

        @Temporal(TemporalType.DATE)
        @DateTimeFormat(pattern="yyyy-MM-dd")
        @Column(name="PARTICULAR_DATE")
        public Date getParticularDate() {
            return particularDate;
        }

        public void setParticularDate(Date particularDate) {
            this.particularDate = particularDate;
        }


    private Date childGoSchoolDate;

        @Temporal(TemporalType.DATE)
        @DateTimeFormat(pattern="yyyy-MM-dd")
        @Column(name="CHILD_GO_SCHOOL_DATE")
        public Date getChildGoSchoolDate() {
            return childGoSchoolDate;
        }

        public void setChildGoSchoolDate(Date childGoSchoolDate) {
            this.childGoSchoolDate = childGoSchoolDate;
        }


    private Date childAdmissionDate;

        @Temporal(TemporalType.DATE)
        @DateTimeFormat(pattern="yyyy-MM-dd")
        @Column(name="CHILD_ADMISSION_DATE")
        public Date getChildAdmissionDate() {
            return childAdmissionDate;
        }

        public void setChildAdmissionDate(Date childAdmissionDate) {
            this.childAdmissionDate = childAdmissionDate;
        }


}
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Assuming that the problem with data type conversion is because MVC uses String, but the actual type is Date.

fth*_*lla 34

在MySql中'0000-00-00'被认为是一个有效的日期,但它不能被重复为java.sql.Date.

您可以使用在日期为的情况下返回NULL的查询'0000-00-00',否则使用实际值:

SELECT
  CASE WHEN `date`!='0000-00-00' THEN `date` END new_date
FROM
  yourtable
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或者您可以添加到您的数据源连接字符串:

zeroDateTimeBehavior=convertToNull
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和日期'0000-00-00'将自动转换为NULL.

  • @ fthiella感谢您的帮助,我们正确的方式,它是generate 0000-00-00而不是null我通过添加到我的数据文件解决它:zeroDateTimeBehavior = convertToNull&autoReconnect = true&characterEncoding = UTF-8&characterSetResults = UTF-8 (5认同)

小智 22

使用JDBC-mysql协议附加以下语句:

"?zeroDateTimeBehavior=convertToNull&autoReconnect=true&characterEncoding=UTF-8&characterSetResults=UTF-8"
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例如:

jdbc:mysql://localhost/infra?zeroDateTimeBehavior=convertToNull&autoReconnect=true&characterEncoding=UTF-8&characterSetResults=UTF-8
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  • 简单而优雅!`private static String url ="jdbc:mysql:// localhost:3306/Your_DB_Name?zeroDateTimeBehavior = convertToNull";` (3认同)

小智 5

添加zeroDateTimeBehavior=convertToNull 到 jdbc 连接 URL。

String jdbcUrl="jdbc:mysql://localhost:3306/master_schema?zeroDateTimeBehavior=convertToNull"
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