Sen*_*nut 0 sql sql-server-2005
HI,
使用Microsoft SQL Server 2005:
我有一个表"测试":
1 11 test1
2 11 test2
3 11 test3
4 12 test4
有没有办法查询这个,并返回由"link_id"分组的结果,并加入名称?
例如,
SELECT link_id,名称FROM test WHERE ???????
结果:
11 test1,test2,test3
12测试4
执行此操作的blackbox方法是使用CROSS APPLY和FOR XML PATH:
declare @t table (id int, link_id int, name varchar(max))
insert into @t select 1, 11, 'test1'
union all select 2, 11, 'test2'
union all select 3, 11, 'test3'
union all select 4, 12, 'test4'
select b.link_id, d.link_names
from (
select distinct link_id
from @t a
) b
cross apply (
select name + ', ' as [text()]
from @t c
where b.link_id = c.link_id
for xml path('')
) d (link_names)
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对于每一行,CROSS APPLY执行应用的子查询.在这种情况下,对于link_id 11和12,子查询被调用两次.子查询然后滥用FOR XML运算符将字符串添加到一起.
如果您运行查询,它将打印:
11 test1, test2, test3,
12 test4,
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