C编程弄清楚bug的位置

Question

伙计帮助我在获取奇数nums的所有产品时遇到问题,每当我输入1,3,2,2时,所有奇数的产品都是0,它不执行1*3 = 3 ...你能不能请指出原因,提前谢谢......

#include <stdio.h>
#include <conio.h>

int main()
{  
int arr[2][2], r, c, sum=0, prod, sumD=0, count=0, count2=0, sumAveEven;

for (r=0; r < 2; r++)
{


    for (c=0; c < 2; c++)
    {
        printf("Enter  Numbers: ");
        scanf("%d", &arr[r][c]);  


        if(r==c)
        {
           sumD = sumD + arr[r][c];  //sum of diagonal pattern

        }   
        if(arr[r][c]%2==0)
        {
          sum = sum + arr[r][c]; //sum ofeven nums  
          count= count +1; 
          sumAveEven = sum / count; 

        }
        else //(arr[r][c]%2 !=0)
        {
           prod = prod * arr[r][c]; //prod of odd nums

        }

        //printf("%d ", arr[r][c]);
    }
   // printf("%d\n", sum);
}
printf("The Sum of All Even Numbers is:  %d \n", sum);
printf("The AVERAGE of All Even Numbers is:  %d \n", sumAveEven);
printf("The product of All Odd Numbers is: %d \n", prod);
printf("The Sum of Elements in pattern Diagonal is: %d \n", sumD);
//printf("Counter: %d \n", count);    
  getch();
  return 0;
}

Answer 1

prod未初始化.您需要将其初始化为1