PHP json_decode问题

Question

我正在尝试使用json_decode组合一些json对象然后重新编码它.我的json看起来像:

{
    "core": {
        "segment": [
            {
                "id": 7,
                "name": "test1" 
            },
            {
                "id": 4,
                "name": "test2" 
            } 
        ] 
    }
}

我有一些这些json对象,并希望只为每个组合"segement"数组得到这样的东西:

{
    "segment": [
        {
            "id": 7,
            "name": "test1" 
        },
        {
            "id": 4,
            "name": "test2" 
        } 
    ],
    "segment": [
        {
            "id": 5,
            "name": "test3" 
        },
        {
            "id": 8,
            "name": "test4" 
        } 
    ]
}

现在在我的PHP代码中,我正在解码json,将每个"segment"数组存储到一个字符串中,然后编码json.

public function handleJSON($json){
        $decodeData = json_decode($json);
        $segment =$decodeData->core;
        return $segment;
}

public function formatJSON(){
        $segments = "";
    for ($i = 0; $i < count($json);$i++)
        {
          $segments .= handleJSON($json[$i]);
        }
    echo json_encode($segments);
}

当我这样做时,我收到一个错误:类stdClass的对象无法转换为字符串

所以我尝试将它们存储在一个数组中:

public function formatJSON(){
        $segments = array();
    for ($i = 0; $i < count($json);$i++)
        {
          $segments[$i] = handleJSON($json[$i]);
        }
    echo json_encode($segments);
}

这一次,我没有得到错误,但它将我的整个组合json对象存储在数组括号中.我怎么能只返回JSON对象,而不是封装在一个数组？

Answer 1

我想一个办法是采取的第二个参数的优势json_decode,assoc:

"当为TRUE时,返回的对象将被转换为关联数组."

我发现通常处理关联数组而不是stdClass类更容易.

$str = '{
   "core": {
        "segment": [
            {
                "id": 7,
                "name": "test1" 
            },
            {
                "id": 4,
                "name": "test2" 
            } 
        ] 
    }
}';
print "<pre>";
print_r(json_decode($str));
print "</pre>";
print "<pre>";
print_r(json_decode($str,true));
print "</pre>";

这首先产生Object版本,然后产生关联数组:

stdClass Object
(
    [core] => stdClass Object
        (
            [segment] => Array
                (
                    [0] => stdClass Object
                        (
                            [id] => 7
                            [name] => test1
                        )

                    [1] => stdClass Object
                        (
                            [id] => 4
                            [name] => test2
                        )

                )

        )

)
Array
(
    [core] => Array
        (
            [segment] => Array
                (
                    [0] => Array
                        (
                            [id] => 7
                            [name] => test1
                        )

                    [1] => Array
                        (
                            [id] => 4
                            [name] => test2
                        )

                )

        )

)

我想我会做类似的事情,创建新的空白数组,解码为关联数组,抓取段成员并将它们拼接到新的空白数组中.所以:

$segments = array();
// assuming you had a bunch of items in the $strings array
foreach ($strings as $str) {
  $item = json_decode($str,true);
  $segments = array_merge($item['core']['segment], $segments);
}

现在,您可以将此编码为json,如下所示:

$final_json = json_encode(array('segments'=>$segments));