Net*_*101 5 .net c# sql insert sql-server-express
基本上我正在做的是,点击按钮后,程序将根据用户选择的内容从特定行中提取数据,并使用它将其放在不同的表中INSERT.以下是代码.
private void button3_Click(object sender, EventArgs e)
{
const String connectionString = "Data Source = Vanessa-PC\\SQLEXPRESS; Initial Catalog = IUMDC; Connect Timeout = 15; Integrated Security = true";
SqlConnection con = new SqlConnection(connectionString);
//int SituationID1;
label24.Show();
foreach (SitID x in Sittbl)
{
if (x.ID == Convert.ToInt16(comboBox1.SelectedItem))
{
try
{
con.Open();
SqlCommand command = new SqlCommand("SELECT * FROM Situation WHERE SituationID=" + x.SitIDs, con);
SqlDataReader dr = command.ExecuteReader();
while (dr.Read())
{
sitid1 = Convert.ToInt32(dr[0]);
name1 = dr[4].ToString();
incident1 = Convert.ToDateTime(dr[1]);
charges1 = dr[5].ToString();
nature1 = dr[2].ToString();
}
con.Close();
}
catch (SqlException ex)
{
MessageBox.Show("Database failed to connect" + ex.Message);
}
//SituationID = x.SitIDs;
}
}
try
{
con.Open();
SqlCommand command1 = new SqlCommand("INSERT INTO CurrentSit VALUES (" + sitid1 + ",'" + incident1.ToString("YYYY-mm-DD") + "', '" + nature1 + "', '" + name1 + "', '" + charges1 + "'", con);
SqlDataReader dr1 = command1.ExecuteReader();
con.Close();
}
catch (SqlException ex)
{
MessageBox.Show("Database failed to connect" + ex.Message);
}
//Situation Sit = new Situation();
//Sit.ShowDialog();
}
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我的代码失败并说
" 行项目附近的语法不正确"
这两个表的类型是相同的,我试图彻底测试这个!
Son*_*nül 18
看起来你的上一个sql语句不正确.也许原因是在你的sql stament中使用撇号,但你不应该关心它.我在答案中解释为什么你不应该在意.
SqlCommand command1 = new SqlCommand("INSERT INTO CurrentSit VALUES (" + sitid1 + ",'" + incident1.ToString("YYYY-mm-DD") + "', '" + nature1 + "', '" + name1 + "', '" + charges1 + "'", con);
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要找出问题的确切原因,可以指定列名.但我建议您使用参数化查询,甚至不需要指定列名.
SqlCommand command1 = new SqlCommand("INSERT INTO CurrentSit VALUES(@sitid1, @incident1, @nature1, @name1, @charges1)", con);
command1.Parameters.AddWithValue("@sitid1", sitid1);
command1.Parameters.AddWithValue("@incident1", incident1.ToString("YYYY-mm-DD"));
command1.Parameters.AddWithValue("@nature1", nature1);
command1.Parameters.AddWithValue("@name1", name1);
command1.Parameters.AddWithValue("@charges1", charges1);
command1.ExecuteNonQuery();
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您应该始终使用参数化查询.这种代码对SQL注入攻击是开放的.
另外正如Marc所提到的,没有必要使用ExecuteReader()这个sql语句,因为它只是INSERT数据,不会返回任何数据.因此,您只需要ExecuteNonQuery()在这种情况下使用.