如何将Scala Seq传递给Java varargs

Question

我有一个像这样的现有Java方法:

public static MyJavaClass javaFunc(String name, long... values) {
    ...
}

我需要用Scala来调用它:

val idList: Seq[Long] = Seq(1L, 2L, 3L)

MyJavaClass.javaFunc("hello", idList)

但它最终会在idList参数上调用toString方法.我试过以下无济于事:

MyJavaClass.javaFunc("hello", idList:_*)

这会导致编译错误:

no `: _*' annotation allowed here (such annotations are only allowed in arguments to *-parameters)

我怎样才能通过论证？

Answer 1

这做到了这一点：

import scala.collection.JavaConverters._
val javaList = idList.asJava