我必须找到列表中是否存在字符串以避免重复插入:以下是来自Microsoft站点的示例:
using System;
using System.Collections.Generic;
public class Example
{
public static void Main()
{
List<string> dinosaurs = new List<string>();
dinosaurs.Add("Compsognathus");
dinosaurs.Add("Amargasaurus");
dinosaurs.Add("Oviraptor");
dinosaurs.Add("Velociraptor");
dinosaurs.Add("Deinonychus");
dinosaurs.Add("Dilophosaurus");
dinosaurs.Add("Gallimimus");
dinosaurs.Add("Triceratops");
Console.WriteLine();
foreach(string dinosaur in dinosaurs)
{
Console.WriteLine(dinosaur);
}
Console.WriteLine("\nTrueForAll(EndsWithSaurus): {0}",
dinosaurs.TrueForAll(EndsWithSaurus));
Console.WriteLine("\nFind(EndsWithSaurus): {0}",
dinosaurs.Find(EndsWithSaurus));
Console.WriteLine("\nFindLast(EndsWithSaurus): {0}",
dinosaurs.FindLast(EndsWithSaurus));
Console.WriteLine("\nFindAll(EndsWithSaurus):");
List<string> sublist = dinosaurs.FindAll(EndsWithSaurus);
foreach(string dinosaur in sublist)
{
Console.WriteLine(dinosaur);
}
Console.WriteLine(
"\n{0} elements removed by RemoveAll(EndsWithSaurus).",
dinosaurs.RemoveAll(EndsWithSaurus));
Console.WriteLine("\nList now contains:");
foreach(string dinosaur in dinosaurs)
{
Console.WriteLine(dinosaur);
}
Console.WriteLine("\nExists(EndsWithSaurus): {0}",
dinosaurs.Exists(EndsWithSaurus));
}
// Search predicate returns true if a string ends in "saurus".
private static bool EndsWithSaurus(String s)
{
return s.ToLower().EndsWith("saurus");
}
}
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是否可以EndsWithSaurus用lambda表达式替换函数?谢谢大家的意见!这是一个有效的代码:
if (dinosaurs.Any(e => e.EndsWith("saurus")))
Console.WriteLine("saurus exists");
if (dinosaurs.Exists(e => e.EndsWith("saurus")))
Console.WriteLine("saurus exists");
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Sev*_*ate 22
试试这个:
if (dinosaurs.Exists(e => e.EndsWith("saurus")))
Console.WriteLine("saurus exists");
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答案也Any()很好.区别在于Exists()方法来自于List<T>自身,而且Any()只是Linq扩展方法之一(并且需要using System.Linq)
D S*_*ley 15
用途Any:
if (dinosaurs.Any(e => e.EndsWith("saurus")))
Console.WriteLine("saurus exists");
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你可以List.Exists()通过改变你的lambda 来使用:
if (dinosaurs.Exists(e => e.EndsWith("saurus")) // == true is implied
Console.WriteLine("saurus exists");
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但是Any更便携(即可以与任何可枚举的,而不仅仅是Lists一起使用).