这个问题一直让我抓狂.我正在尝试使用两个不同的数据集制作散点图.我的数据框是
structure(list(x1 = c(5L, 3L, 4L, 5L, 4L, 8L, 5L, 6L, 3L, 4L,
5L, 6L, 8L, 4L), y1 = c(7L, 5L, 6L, 4L, 1L, 5L, 6L, 9L, 8L, 4L,
5L, 6L, 7L, 8L), class1 = structure(c(1L, 2L, 1L, 1L, 2L, 2L,
2L, 2L, 2L, 1L, 1L, 1L, 1L, 1L), .Label = c("A", "B"), class = "factor"),
x2 = c(4L, 8L, 7L, 5L, 6L, 2L, 5L, 4L, 5L, NA, NA, NA, NA,
NA), y2 = c(7L, 5L, 1L, 4L, 5L, 8L, 4L, 5L, 8L, NA, NA, NA,
NA, NA), class2 = structure(c(3L, 2L, 2L, 2L, 3L, 2L, 2L,
3L, 3L, 1L, 1L, 1L, 1L, 1L), .Label = c("", "A", "B"), class = "factor")), .Names = c("x1",
"y1", "class1", "x2", "y2", "class2"), class = "data.frame", row.names = c(NA,
-14L))
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看起来像这样:
x1 y1 class1 x2 y2 class2
5 7 A 4 7 B
3 5 B 8 5 A
4 6 A 7 1 A
5 4 A 5 4 A
4 1 B 6 5 B
8 5 B 2 8 A
5 6 B 5 4 A
6 9 B 4 5 B
3 8 B 5 8 B
4 4 A
5 5 A
6 6 A
8 7 A
4 8 A
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我想绘制两个散点图:
x1 VS y1x2 VS y2在每个散点图中,我希望符号形状由类class1和class2.由于类是A或者B,我希望符号形状在两个图中保持相同.
我使用以下代码尝试执行此操作:
library(ggplot2)
theme_set(theme_bw()) # omit grey background
qplot(x1, y1, data=df, shape=I(21), fill=I("gray"), size = I(4),alpha = I(0))+
stat_smooth(method="lm", se=FALSE, colour="black", size=1) + geom_point(shape=factor(class1), size=I(4))
qplot(x2, y2, data=df, shape=I(21), fill=I("gray"), size = I(4),alpha = I(0))+
stat_smooth(method="lm", se=FALSE, colour="black", size=1) + geom_point(shape=factor(class2), size=I(4))
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如果我的长度x1/y1和它x2/y2是相同的,它工作正常- 在这种情况下,符号在两个图中保持相同.但是,如果数据集的长度不同(如上面的数据框示例中所示),则在第二个图中引入第三个符号.
有谁知道我怎么可以得到相同的符号A,并B在这两个地块?
编辑:如果我尝试下面由Didzis Elferts建议的方法
ggplot(df,aes(x1,y1,shape=class1))+geom_point(size=4)+
scale_shape_manual(breaks=c("A","B"),values=c(15,16))
ggplot(df,aes(x2,y2,shape=class2))+geom_point(size=4)+
scale_shape_manual(breaks=c("A","B"),values=c(15,16))
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我收到此错误:
Error: Insufficient values in manual scale. 3 needed but only 2 provided.
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编辑2:Didzis Elferts推荐以下解决方案
df$class2<-factor(df$class2,levels=c("A","B"))
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但是,当我尝试使用每个散点图添加回归线时
ggplot(df,aes(x1,y1,shape=class1))+geom_point(size=4)+ scale_shape_manual(breaks=c("A","B"),values=c(15,16))+ stat_smooth(method="lm", se=FALSE, colour="black", size=1)
qplot(x2, y2, data=df, shape=class1)+ stat_smooth(method="lm", se=FALSE, colour="black", size=1) + geom_point(size=4)+ scale_shape_manual(breaks=c("A","B"),values=c(15,16))
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ggplot2为每个类添加一个单独的回归线.相反,我只需要基于来自两个类的数据的单个回归线(即使它们具有不同的符号).
问题是,在您的数据中,class2空单元格是因子级别之一.
str(df$class2)
Factor w/ 3 levels "","A","B": 3 2 2 2 3 2 2 3 3 1 ...
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您可以NA通过设置新的因子级别来更改此空单元格.
df$class2<-factor(df$class2,levels=c("A","B"))
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确保两个图具有相同图例和符号的一种方法是使用scale_shape_manual()然后设置breaks=和values=(形状符号)您需要的方法.
ggplot(df,aes(x1,y1,shape=class1))+geom_point(size=4)+
scale_shape_manual(breaks=c("A","B"),values=c(15,16))
ggplot(df,aes(x2,y2,shape=class2))+geom_point(size=4)+
scale_shape_manual(breaks=c("A","B"),values=c(15,16))
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为了得到只有一个回归线shape=应该直接内放置aes()的geom_point().
ggplot(df,aes(x2,y2))+geom_point(size=4,aes(shape=class2))+
scale_shape_manual(breaks=c("A","B"),values=c(15,16))+
stat_smooth(method="lm", se=FALSE, colour="black", size=1)
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