Bind a char to an enum type

Question

I have a piece of code pretty similar to this:

class someclass
{
public:
enum Section{START,MID,END};
vector<Section> Full;
void ex(){
    for(int i=0;i<Full.size();i++)
    {
        switch (Full[i])
        {
        case START :
                  cout<<"S";
                  break;
        case MID :
                  cout<<"M";
                  break;
        case END:
            cout<<"E";
            break;
        }
    }
    }
};

Now imagine I have much more enum types and their names are longer.... well what i get is not a very good looking code and i was wondering if it possible to bind a specific char to an enum type and maybe do something like this:

for(int i=0;i<Full.size();i++)
    {
        cout<(Full[i]).MyChar();
    }

Or any other method that could make this code "prettier". Is this possible?

Answer 1

不幸的是,你可以做很多事情来清理它.如果您可以访问C++ 11强类型枚举器功能,那么您可以执行以下操作:

enum class Section : char {
     START = 'S',
     MID = 'M',
     END = 'E',
};

然后你可以做类似的事情:

std::cout << static_cast<char>(Full[i]) << std::endl;

但是,如果您无法访问此功能,那么您可以做的事情就不多了,我的建议是拥有一个全局映射std::map<Section, char>,它将每个enum部分与一个字符相关联,或者是一个带有原型的辅助函数:

inline char SectionToChar( Section section );

这只switch()是以更易于访问的方式实现语句,例如:

inline char SectionToChar( Section section ) {
     switch( section )
     {
     default:
         {
             throw std::invalid_argument( "Invalid Section value" );
             break;
         }
     case START:
         {
             return 'S';
             break;
         }
     case MID:
         {
             return 'M';
             break;
         }
     case END:
         {
             return 'E';
             break;
         }
     }
}

Answer 2

在这样的情况下,你可能会很棘手并且施展你的角色.

enum Section{
    START = (int)'S',
    MID   = (int)'M',
    END   = (int)'E'
};

...

inline char getChar(Section section)
{
    return (char)section;
}