GSON.将整数反序列化为整数而不是双精度

Question

我的json对象里面有任意值.我想在Map中反序列化它.除了将整数转换为双打外,一切都很好.见例子:

{"id":1, "inner_obj":{"key":"value","num":666,"map":{"key":"value"}}}

反序列化为this(map.toString()):

{id=1.0, inner_obj={key=value, num=666.0, map={key=value}}}

是否有一些简单的方法将"id"和"num"反序列化为整数而不是双打？

Answer 1

JSON中没有整数类型.1和1.0是相同的.您需要在代码中解析1.0到1.或者您需要将JSON映射到某个VO类并明确定义类的字段类型,以便GSON可以理解您要查找的内容.

Answer 2

我自己一直在寻找嵌套 Map 问题的解决方案，上面的“\xec\x9d\xb4\xec\xa2\x85\xec\x9d\x80”是第一个在非平凡用例中真正有所帮助的答案。

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由于上面的解决方案仅处理数字，因此我更新了该解决方案以提供字符串和布尔值的通用解析功能，请参阅下面更新的代码：

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private static class MapDeserializer implements JsonDeserializer<Map<String, Object>> {\n\n    public Map<String, Object> deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {\n        Map<String, Object> m = new LinkedHashMap<String, Object>();\n        JsonObject jo = json.getAsJsonObject();\n        for (Entry<String, JsonElement> mx : jo.entrySet()) {\n            String key = mx.getKey();\n            JsonElement v = mx.getValue();\n            if (v.isJsonArray()) {\n                m.put(key, g.fromJson(v, List.class));\n            } else if (v.isJsonPrimitive()) {\n                Number num = null;\n                ParsePosition position=new ParsePosition(0);\n                String vString=v.getAsString();\n                try {\n                  num = NumberFormat.getInstance(Locale.ROOT).parse(vString,position);\n                } catch (Exception e) {\n                }\n                //Check if the position corresponds to the length of the string\n                if(position.getErrorIndex() < 0 && vString.length() == position.getIndex()) {\n                  if (num != null) {\n                    m.put(key, num);\n                    continue;\n                  }\n                }\n                JsonPrimitive prim = v.getAsJsonPrimitive();\n                if (prim.isBoolean()) {\n                    m.put(key, prim.getAsBoolean());\n                } else if (prim.isString()) {\n                    m.put(key, prim.getAsString());\n                } else {\n                    m.put(key, null);\n                }\n\n            } else if (v.isJsonObject()) {\n                m.put(key, g.fromJson(v, Map.class));\n            }\n\n        }\n        return m;\n    }\n}\n\nprivate static class ListDeserializer implements JsonDeserializer<List<Object>> {\n\n    public List<Object> deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {\n        List<Object> m = new ArrayList<Object>();\n        JsonArray arr = json.getAsJsonArray();\n        for (JsonElement jsonElement : arr) {\n            if (jsonElement.isJsonObject()) {\n                m.add(g.fromJson(jsonElement, Map.class));\n            } else if (jsonElement.isJsonArray()) {\n                m.add(g.fromJson(jsonElement, List.class));\n            } else if (jsonElement.isJsonPrimitive()) {\n                Number num = null;\n                try {\n                    num = NumberFormat.getInstance().parse(jsonElement.getAsString());\n                } catch (Exception e) {\n                }\n                if (num != null) {\n                    m.add(num);\n                    continue;\n                }\n                JsonPrimitive prim = jsonElement.getAsJsonPrimitive();\n                if (prim.isBoolean()) {\n                    m.add(prim.getAsBoolean());\n                } else if (prim.isString()) {\n                    m.add(prim.getAsString());\n                } else {\n                    m.add(null);\n                }\n            }\n        }\n        return m;\n    }\n}\n\nprivate static Gson g = new GsonBuilder().registerTypeAdapter(Map.class, new MapDeserializer()).registerTypeAdapter(List.class, new ListDeserializer()).setDateFormat("yyyy-MM-dd HH:mm:ss").create();\n

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