Vyt*_*kas 0 javascript jquery loops
不知道如何做到这一点否则......但这就是我想要做的:
我有一系列的收音机盒
<div id="xrowcont_0">
<input type="radio" name="13_641" value="a" id="13_641_form_a" ><label for="13_641_form_a"><span></span></label>
<input type="radio" name="13_641" value="b" id="13_641_form_b" checked="checked"><label for="13_641_form_b"><span></span></label>
<div id="xmod_mach_list_0" style="display:none;">BOO1</div>
</div>
<div id="xrowcont_1">
<input type="radio" name="13_642" value="a" id="13_642_form_a"><label for="13_642_form_a"><span></span></label>
<input type="radio" name="13_642" value="b" id="13_642_form_b"><label for="13_642_form_b"><span></span></label>
<div id="xmod_mach_list_1" style="display:none;">BOO2</div>
</div>
... ++++
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并且想法是当你在中选择单选框"B"时<div id="xrowcont_0">,它会<div id="xmod_mach_list_1"在每行旁边取消隐藏.
这是js:
可以说我们有13排......
for (var i=0;i<13;i++) {
var a1 = "'#xrowcont_" + [i] + " input[type=radio]'";
var a2 = "'#xrowcont_" + [i] + " input:checked'";
console.log(a1);
console.log(a2); // these show up just fine.
$(a1).on( "click", function() { // but here it breaks.
var state = $(a2).val();
if (state == "b") {
$('#xmod_mach_list_' + [i] ).css('opacity',0).show().animate({ opacity: 1 }, 300);
console.log("Show Button");
} else {
$('#xmod_mach_list_' + [i] ).animate({ opacity: 0} , 200);
setTimeout(function () {$('#xmod_mach_list_' + [i] ).hide(); }, 200);
console.log("Hide Button");
};
});
}
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它给了我Uncaught Error: Syntax error, unrecognized expression: '#xrowcont_0 input[type=radio]',虽然这就是我想要填充的... $(a1).on( "click", function() {...部分等等.
我怎样才能解决这个问题?
取下支架.[i]是一个包含i唯一项目的数组.
你还应该注意,由于封闭的魔力,i在一个setTimeout意志中使用会导致问题.考虑像这样形成你的循环:
for(i ......) { (function(i) {
...
})(i); }
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