POST到C#时JSON对象为空

Question

jQuery的:

$('#test').click(function () {

    var obj = new Object();
    var childObj = new Object();

    childObj.name = 'dominic';
    childObj.age = 22;

    obj.children = new Object ({ child : childObj });

    console.log(obj);

    $.ajax({
        url: '@Url.Action("Test")',
        type: 'POST',
        data: obj,
        dataType: 'json',
        success: function (msg) {
            //console.log(msg.status);
        }
    });

});

C#(MVC 4):

public JsonResult Test(testObj obj)
{
    foreach (childObj child in obj.children)
    {
        Debug.Print(child.name);
        Debug.Print(child.age);
    }

    return Json(null);
}

public class testObj
{
    public List<childObj> children { get; set; }
}

public class childObj
{
    public string name { get; set; }
    public string age { get; set; }
}

当我调试时,obj有一个children属性,但它总是null ...在我的浏览器控制台中,它不是null ...

Answer 1

首先,我建议您将复杂对象从客户端发送到服务器作为JSON:

$.ajax({
    url: '@Url.Action("Test")',
    type: 'POST',
    contentType: 'application/json',
    data: JSON.stringify(obj),
    dataType: 'json',
    success: function (msg) {
        //console.log(msg.status);
    }
});

需要注意的事项:

1. contentType: 'application/json'
2. data: JSON.stringify(obj)

此外children,客户端上的属性必须是数组,而不是属性:

var obj = {};
var childObj = {};

childObj.name = 'dominic';
childObj.age = 22;

obj.children = [];
obj.children.push(childObj);

或者干脆:

var obj = {
    children: [
        { name: 'dominic', age: 22 }
    ]
};

另一个注释:在服务器上,您的Age属性被定义为字符串,而在客户端上,您将它作为integer(age: 22)传递,这是不一致的.除此之外,您不需要将所有C#属性都放在小写中.那太可怕了.JavaScriptSerializer足够智能,可以遵守标准的C#命名约定:

public class TestObj
{
    public List<ChildObj> Children { get; set; }
}

public class ChildObj
{
    public string Name { get; set; }
    public string Age { get; set; }
}