似乎显而易见的结构将是这样的:
while (current_time < end_time) {
current_number = *next_number++;
if (meets_conditions(current_number))
output(current_number);
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
80 次 |
| 最近记录: |