将IEnumerable <Task <T >>转换为IObservable <T>

Question

我正在尝试使用Reactive Extensions(Rx)在任务完成时缓冲它们的枚举.有谁知道是否有一个干净的内置方式这样做？该ToObservable扩展方法只会让一IObservable<Task<T>>,这不是我想要的,我想要的IObservable<T>,我可以再使用Buffer的.

举例:

//Method designed to be awaitable
public static Task<int> makeInt()
{
     return Task.Run(() => 5);
}

//In practice, however, I don't want to await each individual task
//I want to await chunks of them at a time, which *should* be easy with Observable.Buffer 
public static void Main() 
{
    //Make a bunch of tasks
    IEnumerable<Task<int>> futureInts = Enumerable.Range(1, 100).Select(t => makeInt());

    //Is there a built in way to turn this into an Observable that I can then buffer?
    IObservable<int> buffered = futureInts.TasksToObservable().Buffer(15); //????

    buffered.Subscribe(ints => {
        Console.WriteLine(ints.Count()); //Should be 15
    });
}

Answer 1

您可以使用Task可以使用另一个重载ToObservable()转换为observable 的事实.

如果有(单项)可观察对象的集合,则可以创建一个包含完成后使用的项目的可观察对象Merge().

所以,你的代码看起来像这样:

futureInts.Select(t => t.ToObservable())
          .Merge()
          .Buffer(15)
          .Subscribe(ints => Console.WriteLine(ints.Count));