在列表中没有分隔符的多个分隔符处拆分

Question

这应该是使用re库的一个非常简单的任务.不过,我似乎无法到我的字符串的分隔符分裂]和[.

我已经读过在Python中拆分带有多个分隔符的字符串,Python:带有多个分隔符的拆分字符串,以及Python:如何在方括号内获取多个元素.

我的字符串:

data = "This is a string spanning over multiple lines.
        At somepoint there will be square brackets.

        [like this]

        And then maybe some more text.

        [And another text in square brackets]"

它应该返回:

['This is a string spanning over multiple lines.\nAt somepoint there will be square brackets.','like this', 'And then maybe some more text.', 'And another text in square brackets']

一个简短的例子:

data2 = 'A new string. [with brackets] another line [and a bracket]'

我试过了:

re.split(r'(\[|\])', data2)
re.split(r'([|])', data2)

但是这些会导致我的结果列表中的分隔符或完全错误的列表:

['A new string. ', '[', 'with brackets', ']', ' another line ', '[', 'and a bracket', ']', '']

结果应该是:

['A new string.', 'with brackets', 'another line', 'and a bracket']

作为特殊要求,应删除分隔符之前和之后的所有换行符和空格,并且不应包括在列表中.

Answer 1

>>> re.split(r'\[|\]', data2)
['A new string. ', 'with brackets', ' another line ', 'and a bracket', '']

Answer 2

正如 arshajii 指出的那样，对于这个特定的正则表达式，您根本不需要组。

如果确实需要组来表达更复杂的正则表达式，则可以使用非捕获组进行拆分而不捕获分隔符。它可能对其他情况有用，但在这里语法上凌乱过度。

（？：……）

A non-capturing version of regular parentheses. Matches whatever regular expression is inside the parentheses, but the substring matched by the group cannot be retrieved after performing a match or referenced later in the pattern.

http://docs.python.org/2/library/re.html

所以这里不必要的复杂但具有示范性的例子是：

re.split(r'(?:\[|\])', data2)