kin*_*er1 1 c linux linux-device-driver
我正在摆弄scull驱动程序代码,然后试图让它打印输入的整个字符,而不是一个.这就是:
# insmod memory.ko
# chmod 666 /dev/memory
$ echo -n abcdef >/dev/memory
$ cat /dev/memory
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应该打印abcdef,而是打印f
为此,我对scull代码进行了修改:
ssize_t memory_read(struct file *filp, char *buf,
size_t count, loff_t *f_pos) {
/* Transfering data to user space */
copy_to_user(buf,memory_buffer,5);
/* Changing reading position as best suits */
if (*f_pos == 0) {
*f_pos+=1;
return 1;
} else {
return 0;
}
}
ssize_t memory_write( struct file *filp, char *buf,
size_t count, loff_t *f_pos) {
char *tmp;
tmp=buf+count-1;
copy_from_user(memory_buffer,tmp,5);
return 1;
}
int memory_init(void) {
int result;
/* Registering device */
result = register_chrdev(memory_major, "memory", &memory_fops);
if (result < 0) {
printk(
"<1>memory: cannot obtain major number %d\n", memory_major);
return result;
}
/* Allocating memory for the buffer */
memory_buffer = kmalloc(5, GFP_KERNEL);
if (!memory_buffer) {
result = -ENOMEM;
goto fail;
}
memset(memory_buffer, 0, 5);
printk("<1>Inserting memory module\n");
return 0;
fail:
memory_exit();
return result;
}
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在read未正确执行.它不应该count向用户写入更多的字节(他可以使用更小的缓冲区).更相关的是,它应该返回写入用户的字节数,并且0只有在文件结束时才返回.它也可以将错误代码作为负数返回,就像-EIO发生错误一样.
你写了5个字符,但返回1,所以cat认为它是不完整的读取,读取1个字节.我尝试再次读取并获得0,因此它将其解释为文件末尾.
write 有类似的问题,它还应该检查用户缓冲区的大小和返回字节数.
这或多或少是我read为固定大小的缓冲区实现的:
ssize_t memory_read(struct file *filp, char *buf,
size_t count, loff_t *f_pos) {
ssize_t retval;
if(down_interruptible(&sem)) // some mutex is probably necessary
return -ERESTARTSYS;
count = MIN(count, MEMORY_SIZE - *f_pos);
if(count == 0) { // this if is probably not necessary
retval = 0;
goto out;
}
/* Transfering data to user space */
if(copy_to_user(buf, memory_buffer + *f_pos, count)) {
retval = -EFAULT;
goto out;
}
*f_pos += count;
retval = count;
out:
up(&sem);
return retval;
}
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