如何从字符串中移除{{}}内的内容 - PHP

Question

我有一个字符串

$data = "{{quickbar | image=Baby Beach Aruba.JPG | caption=Baby Beach | location=LocationAruba.png | flag=Flag of Aruba.svg | capital=Oranjestad | government=parliamentary democracy | currency=Aruban guilder/florin (AWG) | area=193 sq km | population=71,891 (July 2006 est.) | language=Dutch (official), Papiamento (a creole of Spanish, Portuguese, and Dutch origin), English (widely spoken), Spanish | religion=Roman Catholic 82%, Protestant 8%, Hindu, Muslim, Confucian, Jewish | electricity=120V/60Hz (North American plug) | callingcode=+297 | tld=.aw | timezone=UTC -4 }} Aruba [1] is a Caribbean island 15 miles north of the coast of Venezuela. The island is an autonomous dependency of the Kingdom of the Netherlands.";

我想删除{{}}内的所有内容以及括号内的所有内容

我期待这样

$data = "Aruba [1] is a Caribbean island 15 miles north of the coast of Venezuela. The island is an autonomous dependency of the Kingdom of the Netherlands.";

Answer 1

如果这些括号不能嵌套,那很简单:

$result = preg_replace('/\{\{.*?\}\}\s*/s', '', $subject);

如果可以的话,你需要一个递归的正则表达式:

$result = preg_replace('/\{\{(?:(?:(?!\{\{|\}\}).)*+|(?R))+\}\}\s*/', '', $subject);

说明:

{{          # Match {{
(?:         # Either match...
 (?:        # the following regex:
  (?!{{|}}) # Unless we're at the string {{ or }},
  .         # match any character
  )*+       # any number of times (possessively to avoid backtracking).
 |          # Or match...
 (?R)       # whatever this entire regex matches (recursively)
)+          # End of alternation, repeat as necessary
}}          # Match }}
\s*         # Match optional trailing whitespace

在regex101.com上查看.