XmlReader如何在C#中工作

Question

我正在尝试从我制作的字符串中读取一些Xml,但实际上任何Xml文件都可以.

我只是想浏览Xml节点,就像它是一个多维矩阵,并最终将它们放在DataTable中(将它们放在带有SqlBulkCopy的sql server中).我已经在MSDN和周围看了一下.有人能解释清楚简单吗？

这是代码:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Data;
using System.Xml;
using System.IO;

namespace ConsoleApplication2
{
    class Program
    {
        private static DataTable table = new DataTable();
        private static String xmlString =
        @"<?xml version='1.0'?>
        <!-- This is a sample XML document -->
        <Garage>
            <Car>
                <Name>Ferrari</Name>
                <Speed>360km/h</Speed>
                <Engine>Ferrari Enzo</Engine>
                <Color>Red</Color>
                <Year>1999</Year>
            </Car>
            <Car>
                <Name>Maserati</Name>
                <Speed>270km/h</Speed>
                <Color>Metal Grey</Color>
                <Year>2007</Year>
            </Car>
            <Car>
                <Name>Limo</Name>
                <Color>Black</Color>
                <Engine>Chevrolet</Engine>
                <Year>2007</Year>
            </Car>
        </Garage>";

        static void Main(string[] args)
        {
            Program x = new Program();
            XmlReader reader = XmlReader.Create(new StringReader(xmlString));
            while (reader.Read())
            {
                if (reader.NodeType == XmlNodeType.Element)
                {
                    Console.WriteLine(XmlNodeType.Element.ToString());
                    }
                }
            }

        }
    }

我想循环整个事情,得到类似的东西:

名称:法拉利速度:360km/h发动机:法拉利恩佐

等等,你得到了演练.

Answer 1

System.Xml.Linq.XDocument.Parse(string)会给你一个XDocument. XDocument.Root将为XElement您提供文档的根目录.我想你会发现这很容易合作.

您正在尝试使用上一代的XML工具.NET -较新XDocument,XElement等工具都平易近人得多.

示例代码

using System.Xml.Linq;
...
var root = XDocument.Parse(xmlString).Root;

var cars = root
    .ToAll("Car")
    .Select(car => new
    {
        Name = car.ToFirst("Name").Value,
        Speed = car.ToAll("Speed").Any() ? car.ToFirst("Speed").Value : null,
        Color = car.ToFirst("Color").Value,
        Engine = car.ToFirst("Engine").Value,
        Year = int.Parse(car.ToFirst("Year").Value)
    })
    .ToList();

助手班

public static class XmlHelper
{
    public static XNode ReadFrom(Stream stream)
    {
        using (var xmlReader = XmlReader.Create(stream))
            return XDocument.Load(xmlReader);
    }

    public static void WriteTo(Stream stream, XNode node)
    {
        using (var xmlWriter = XmlWriter.Create(stream))
            node.WriteTo(xmlWriter);
    }

    public static XElement ToFirst(this XElement ancestor, String descendantLocalName)
    {
        return ancestor.Descendants().FirstOrDefault(element => element.Name.LocalName == descendantLocalName);
    }

    public static IEnumerable<XElement> ToAll(this XElement ancestor, String descendantLocalName)
    {
        return ancestor.Descendants().Where(element => element.Name.LocalName == descendantLocalName);
    }

    public static string ToAttribute(this XElement element, string name)
    {
        var attribute = element.Attribute(XName.Get(name));
        return attribute != null ? attribute.Value : null;
    }
}