openssl:我如何从模数中获取公钥

Mik*_*e.G 2 php openssl rsa modulus

我使用openssl生成一对密钥:

shell> ssh-keygen -t rsa
Generating public/private rsa key pair.
Enter file in which to save the key (/Users/mike/.ssh/id_rsa): /path/to/test_rsa
Enter passphrase (empty for no passphrase): 
Enter same passphrase again: 
Your identification has been saved in /path/to/test_rsa.
Your public key has been saved in /path/to/test_rsa.pub.
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然后,我从私钥生成模数:

shell> openssl rsa -in /path/to/test_rsa -noout -modulus > /path/to/modulus.txt
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现在,有没有办法从模数中获取test_rsa.pub(公钥)?

neu*_*ert 7

您可以使用纯PHP PHP实现的phpseclib以更标准化的格式获取公钥.例如.

<?php
include('Crypt/RSA.php');

$modulus = 'yEQs2LxSHBZgZCH0rRQQy9kmry8g2tNhQL1B9f5azNz9Ce9pXPgSRjVUo1B9Ggb/FK3jy41wWd2IfS6rse3vBzRsabMj29CVODM/19yZPmwEmjJHCgYd+AA2qweKZanDp4FLsSw/kyV5WoPN16GHEMLmLGkJFNIWtzzH5jV+S80=';
$exponent = 'AQAB';

$rsa = new Crypt_RSA();

$modulus = new Math_BigInteger(base64_decode($modulus), 256);
$exponent = new Math_BigInteger(base64_decode($exponent), 256);

$rsa->loadKey(array('n' => $modulus, 'e' => $exponent));
$rsa->setPublicKey();

echo $rsa->getPublicKey();
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  • 有没有一种方法可以在没有phpseclib库的情况下实现这一目标? (2认同)