使用字符串中的整数来创建具有那么多数字的字典(或列表)

Question

所以我有这个由数字和单词组成的文本(wordnet)文件,例如像这样 -

"09807754 18 n 03 aristocrat 0 blue_blood 0 patrician"

我想在第一个数字中读取后续单词的字典名称(或列表).它的布局永远不会改变,它始终是一个8位数的键,后跟一个两位数字,一个字母和一个两位数字.最后两位数字(03)表示有多少单词(在这种情况下为三个单词)与前8位数字键相关联.

我的想法是,我会搜索字符串中的第14位并使用该数字运行循环来挑选与该键相关的所有单词

所以我认为它会像这样

with open('nouns.txt','r') as f:
    for line in f:

        words = range(14,15)
        numOfWords = int(words)
            while i =< numOfWords
                #here is where the problem arises, 
                #i want to search for words after the spaces 3 (numOfWords) times 
                #and put them into a dictionary(or list) associated with the key
                range(0,7) = {word(i+1), word(i+2)}

从技术上讲,我正在寻找其中任何一个更有意义:

09807754 = { 'word1':aristocrat, 'word2':blue_blood , 'word3':patrician }
or
09807754 = ['aristocrat', 'blue_blood', 'patrician']

显然这不会运行,但如果有人能给我任何指针,将不胜感激

Answer 1

>>> L = "09807754 18 n 03 aristocrat 0 blue_blood 0 patrician".split()
>>> L[0], L[4::2]
('09807754', ['aristocrat', 'blue_blood', 'patrician'])

>>> D = {}
>>> D.update({L[0]: L[4::2]})
>>> D
{'09807754': ['aristocrat', 'blue_blood', 'patrician']}

对于评论中的额外行,需要一些额外的逻辑

>>> L = "09827177 18 n 03 aristocrat 0 blue_blood 0 patrician 0 013 @ 09646208 n 0000".split()
>>> D.update({L[0]: L[4:4 + 2 * int(L[3]):2]})
>>> D
{'09807754': ['aristocrat', 'blue_blood', 'patrician'], '09827177': ['aristocrat', 'blue_blood', 'patrician']}