如何删除NSString中包含括号()的子字符串？

Question

我有以下NSString:

Hello (my name is) John

如何(my name is)快速轻松地拆卸零件？我想确保它处理只有a (然后跟随)并且不会崩溃的情况.

Answer 1

如果要删除括号中的文本,那么......好吧,删除括号中的文本.

NSMutableString *s = [NSMutableString stringWithString:@"Hello (my name is) John"];
NSRange start = [s rangeOfString:@"("];
NSRange end = [s rangeOfString:@")"];
[s deleteCharactersInRange:(NSRange){ start.location, end.location - start.location + 1}];

(重复过程,直到有parens)

Answer 2

使用正则表达式(贪婪)很容易做到:

NSError *error = NULL;
NSString *stringToBeReplaced = @"Hello (my name is) John";
NSString *regexString = @"\\(.*\\)";
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:regexString options:NSRegularExpressionCaseInsensitive error:&error];
NSString *modifiedString = [regex stringByReplacingMatchesInString:stringToBeReplaced options:0 range:NSMakeRange(0, [stringToBeReplaced length]) withTemplate:@""];
// Greedy means it will match "My name (is John) (Jobs)." => "My name ."

对于非贪婪的正则表达式,请使用:

NSString *regex = @"\\(.*?\\)";