Joh*_*erz 47 python string split
所以我有这个文本文件由数字和单词组成,例如像这样 - 09807754 18 n 03 aristocrat 0 blue_blood 0 patrician我想拆分它,以便每个单词或数字都会作为一个新行出现.
一个空白分隔符是理想的,因为我希望带有破折号的单词保持连接.
这是我到目前为止:
f = open('words.txt', 'r')
for word in f:
print(word)
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我不确定如何离开这里,我希望这是输出:
09807754
18
n
3
aristocrat
...
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daw*_*awg 124
如果您的数据周围没有引号,并且您一次只想要一个单词(忽略文件中空格与换行符的含义):
with open('words.txt','r') as f:
for line in f:
for word in line.split():
print(word)
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如果需要文件每行中单词的嵌套列表(例如,要从文件创建行和列的矩阵):
with open("words.txt") as f:
[line.split() for line in f]
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或者,如果要将文件展平为文件中单个单词的平面列表,则可以执行以下操作:
with open('words.txt') as f:
[word for line in f for word in line.split()]
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如果你想要一个正则表达式解决方案:
import re
with open("words.txt") as f:
for line in f:
for word in re.findall(r'\w+', line):
# word by word
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或者,如果您希望它是带有正则表达式的逐行生成器:
with open("words.txt") as f:
(word for line in f for word in re.findall(r'\w+', line))
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dug*_*res 18
f = open('words.txt')
for word in f.read().split():
print(word)
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pam*_*bda 12
作为补充,如果您正在阅读vvvvery大文件,并且您不希望一次将所有内容读入内存,您可以考虑使用缓冲区,然后按yield返回每个单词:
def read_words(inputfile):
with open(inputfile, 'r') as f:
while True:
buf = f.read(10240)
if not buf:
break
# make sure we end on a space (word boundary)
while not str.isspace(buf[-1]):
ch = f.read(1)
if not ch:
break
buf += ch
words = buf.split()
for word in words:
yield word
yield '' #handle the scene that the file is empty
if __name__ == "__main__":
for word in read_words('./very_large_file.txt'):
process(word)
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你可以做的是使用 nltk 来标记单词,然后将所有单词存储在一个列表中,这就是我所做的。如果你不知道 nltk; 它代表自然语言工具包,用于处理自然语言。如果你想开始,这里有一些资源 [ http://www.nltk.org/book/]
import nltk
from nltk.tokenize import word_tokenize
file = open("abc.txt",newline='')
result = file.read()
words = word_tokenize(result)
for i in words:
print(i)
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输出将是这样的:
09807754
18
n
03
aristocrat
0
blue_blood
0
patrician
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