如何用jquery添加div的副本？

Question

我有一个div包含一些动态生成的下拉列表.

我想克隆它并将其添加到原始下面.原始代码是:

<div id="subjectselectiondiv" style="width:inherit;">
    <h4>Select the subjects that you are able to tutor</h4>
    <div id='choices'>
        <script type="text/javascript">
            var doc = document.getElementById("choices");
            var subj_div = document.createElement('div');
            subj_div.setAttribute('class', 'selectSearchBar');
            subj_div.innerHTML = '<select id="level'+counter+'" name="level'+counter+'" class="selectSearchBar"><?php echo "<option>Level</option>"; while($row = mysqli_fetch_array($result_level, MYSQLI_ASSOC)){echo "<option value=".$row['id'].">".$row['level']."</option>";}?></select><div id="subject'+counter+'" style="display:inline;">sBar2</div><div id="topic'+counter+'" style="display:inline;">sbar3</div>';
            doc.appendChild(subj_div);
        </script>
    <a href='#' class="more" onclick="Repeat()">Add another subject</a>
</div>

我认为函数Repeat()可以用于:

function Repeat(){
    counter++;
    $('#choices').clone().appendTo('#subjectselectdiv');
    event.preventDefault();
}

但这不起作用 - 我错过了什么吗？

谢谢

Answer 1

名称不匹配:

<div id="subjectselectiondiv" style="width:inherit;">
                     ^^^^^^
$('#choices').clone().appendTo('#subjectselectdiv');
                                            ^^^

您尝试附加的内容不存在.最有可能的是,如果你打扰检查你的javascript控制台,你会看到关于不存在的元素的警告/错误.