Scala Play表单验证:一个案例类的不同表单 - 是否可能？

Question

我正在寻找一种方法,为一个案例类使用两种不同的形式.我试图用额外的构造函数做到这一点,但失败了.看一下代码片段:

case class LoginDetails(password: String, field3: Option[Int], field4: String)

case class User(username: String, loginDetails: LoginDetails) {
   def this(username: String, password: String, field3: Option[Int], field4: String) = this(username, LoginDetails(password, field3, field4))
// some logic inside
    }

val loginDetailsForm = Form(
 mapping(
   "password" -> text,
   "field3" -> optional(number),
   "field4" -> text
 )(LoginDetails.apply)(LoginDetails.unapply))

val oldForm = Form(
 mapping(
   "username" -> email,
   "password" -> text,
   "field3" -> optional(number),
   "field4" -> text
 )(User.apply)(User.unapply))

val newForm = Form(
     mapping(
       "username" -> email,
       "loginDetails" -> loginDetailsForm.mapping
     )(User.apply)(User.unapply))

我要做的是支持两个API(新的和旧的),但如果我将拥有相同案例类的两个副本,我将不得不在其余的代码中的许多地方重复代码逻辑.如果有办法做到这一点？

当然,鉴于代码不起作用,并像一个例子一样使用.

谢谢!

Answer 1

您可以尝试添加方法applyOld和unapplyOld伴侣对象,如下所示:

case class User(username: String, loginDetails: LoginDetails)
object User {
  def applyOld(username: String, password: String, field3: Option[Int], field4: String) = new User(username, LoginDetails(password, field3, field4))
  def unapplyOld(u: User): Option[(String, String, Option[Int], String)] =
    Some((u.username, u.loginDetails.password,  u.loginDetails.field3,  u.loginDetails.field4))
}

你只需要方法(String, String, Option[Int], String) => User和User => Option[(String, String, Option[Int], String)],你可以在任何地方,你喜欢把他们.例如,您可以UserOld使用方法apply和创建对象unapply.

用法:

val oldForm = Form(
 mapping(
   "username" -> email,
   "password" -> text,
   "field3" -> optional(number),
   "field4" -> text
 )(User.applyOld)(User.unapplyOld))

val newForm = Form(
     mapping(
       "username" -> email,
       "loginDetails" -> loginDetailsForm.mapping
     )(User.apply)(User.unapply))